All categories

3 years ago

Please help I’ll make you a branliest!!!!!!!

Mathematics

1 answer:

masya89 [10]3 years ago

7 0

Answer:

2 answer is right

Step-by-step explanation:

I think

You might be interested in

What is the range of this data set? 2.1, 2.6, 7.2, 5.5, 4.1, 5.5, 7.5, 6.1

spin [16.1K]

You have to subtract the largest number from the smallest and you get your range. Which would be 7.5-2.1 equals 5.4 which is b.

4 0

3 years ago

Read 2 more answers

Find the 53rd term of the arithmetic sequence<br> 27,11, -5

vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

3 0

3 years ago

A 273,000-gallon shipment of fuel is 2.3 percent

-Dominant- [34]

Answer:

Amount of fuel antifreeze = 6,279 gallon

Step-by-step explanation:

Given:

Amount of fuel = 273,000-gallon

Antifreeze = 2.3 %

Find:

Amount of fuel antifreeze

Computation:

Amount of fuel antifreeze = Amount of fuel × Antifreeze

Amount of fuel antifreeze = 273,000 × 2.3 %

Amount of fuel antifreeze = 6,279 gallon

8 0

4 years ago

Is 6-6 and 1-6 equal

uranmaximum [27]

Answer:

Step-by-step explanation:

6-6=0

1-6=-5

7 0

3 years ago

Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

7 0

3 years ago