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3 years ago

These box plots show daily low temperatures for a sample of days in two

Mathematics

1 answer:

9966 [12]3 years ago

6 0

Answer:

B. The interquartile range (IQR) for town A, 20, is greater than the

IQR for town B, 10.

Step-by-step explanation:

IQR = Q₃ - Q₁

For the town A:

Q₃ = 40 and Q₁ = 20

IQR of town A = 40 - 20 = 20

For the town B:

Q₃ = 30 and Q₁ = 20

IQR of town A = 30 - 20 = 10

Check the given options:

The most statement is appropriate comparison of the spreads is B

B. The interquartile range (IQR) for town A, 20, is greater than the

IQR for town B, 10.

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Read 2 more answers

Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

ololo11 [35]

Answer:

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

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2 years ago