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The answer is -5, -5 added by 5 cancels each other out. Then when you add 4x + 8x, you get 12x. So when you do 12x= -60, you get -5.
<span>The basis of this cone is a circle with a diameter d = 16m. This information is sufficient to calculate
1. The surface of the wheel . We use the formula
</span>
<span>
2. </span><span>the radius of the wheel needed to the formula for calculating the area of a circle and the cone
d = 16m
1/2d = r = 1/2*16m = 8m
..................................................................................................
Area base
</span>
<span>..................................................................................................
</span><span>The surface area
</span>
<span>l - creates a cone = ?
</span><span>Height , forming a cone and the radius of a circle formed triangle . Two known sides is possible to calculate the third side ( the cone ) of the Pythagorean Theorem
</span>
a = r = 8cm
b = h = 24m
c = l = ?
a² + b² = c²
r² + h² = l²
l = √ (r² + h²) = √ [ ( 8m)² + ( 24m)² ] = √ (64m² + 576m²) = √ (640 m²)= √ (8*8*10m²) = 8√10m
<span>The lateral surface of the cone
A = </span>πrl = π*8m *8√10m = 64√10πm²
The total area of the cone = <span>The base area of the side surface of +
A = 64</span>√10πm² + 64πm² = 64πm² *(√10 + 1)
1. The surface of the wheel . We use the formula
</span>
<span>
2. </span><span>the radius of the wheel needed to the formula for calculating the area of a circle and the cone
d = 16m
1/2d = r = 1/2*16m = 8m
..................................................................................................
Area base
</span>
<span>..................................................................................................
</span><span>The surface area
</span>
<span>l - creates a cone = ?
</span><span>Height , forming a cone and the radius of a circle formed triangle . Two known sides is possible to calculate the third side ( the cone ) of the Pythagorean Theorem
</span>
a = r = 8cm
b = h = 24m
c = l = ?
a² + b² = c²
r² + h² = l²
l = √ (r² + h²) = √ [ ( 8m)² + ( 24m)² ] = √ (64m² + 576m²) = √ (640 m²)= √ (8*8*10m²) = 8√10m
<span>The lateral surface of the cone
A = </span>πrl = π*8m *8√10m = 64√10πm²
The total area of the cone = <span>The base area of the side surface of +
A = 64</span>√10πm² + 64πm² = 64πm² *(√10 + 1)