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3 years ago

hey can someone help me with this immediately! i’ll be giving out brainiest if u don’t leave a link and don’t guess!

Mathematics

1 answer:

zzz [600]3 years ago

6 0

Answer:

2(209 + 467) - 9/10

Step-by-step explanation:

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joe has a rectangular patio that measures 4 feet by 6 feet. he plants to double the area of the patio by increasing each dimensi

ivanzaharov [21]

The new dimensions will be 8 which is (4) and 12 which is (6) so the area is 96 feet squared.

4 0

3 years ago

Complete the following: a^2 − 16 = (a +______ )(a - _____ )

snow_tiger [21]

Answer:

$a^{2} -16$ = (a + <u>4</u>) (a - <u>4</u>)

Step-by-step explanation:

The given equation is $a^{2} -16$

Now, By ALGEBRAIC IDENTITY:

$a^{2} -b^{2} =(a - b) (a + b)$

Here, taking $b^{2} = 16$ , we get b = 4

as $4^{2} = 16$

So, the right hand side of $a^{2} -16$ is (a + 4) (a-4)

7 0

4 years ago

I need it badly as soon as possible if you can ASAP

Softa [21]

The answers are:

9:D

10:C

Have a good day! (or night, depending when u see this)

4 0

4 years ago

What postulate or theorem can be used to prove that LMN = PMN

uranmaximum [27]

It depends on how it's used.
For example if it's angles it could be because of Vertical Angles.
If it's Triangles it could be Definition of Congruent Triangles.

8 0

3 years ago

Two bicycles are traveling along perpendicular roads. Bicycle A is traveling due east at 4 mi/hr, and bicycle B is travelling du

nordsb [41]

Answer:

Step-by-step explanation:

Given

speed of cyclist A is $v_a=4 mi/hr$

speed of cyclist B is $v_b=6 mi/hr$

At noon cyclist B is 9 mi away

after noon Cyclist B will travel a distance of 6 t and cyclist A travel 4 t miles in t hr

Now distance of cyclist B from intersection is 9-6t

Distance of cyclist A from intersection is 4 t

let distance between them be z

$z^2=(9-6t)^2+(4t)^2$

Differentiate z w.r.t time

$2z\frac{\mathrm{d} z}{\mathrm{d} t}=2\times (9-6t)\times (-6)+2\times (4t)\times 4$

$z\frac{\mathrm{d} z}{\mathrm{d} t}=(-6)(9-6t)+4(4t)$

$\frac{\mathrm{d} z}{\mathrm{d} t}=\frac{16t+36t-54}{z}$

Put $\frac{\mathrm{d} z}{\mathrm{d} t}\ to\ get\ maximum\ value\ of\ z$

therefore $52t-54=0$

$t=\frac{54}{52}$

$t=\frac{27}{26} hr$

4 0

3 years ago