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laila [671]
3 years ago
15

Given a graph of a function, explain how to find the rate of change and how to determine whether it is a linear or nonlinear fun

ction.
Mathematics
2 answers:
cluponka [151]3 years ago
5 0
To determine wether of not it is linear, you will need to see if it has a constant rate of change, if it does it is a linear function, if it doesn't it is non-linear. and to find the rate of change you will need to find the slope.
chubhunter [2.5K]3 years ago
4 0

To find the rate of change, count the rise and run between two points. Then divide the rise by the run. If the rate of change is constant between all points, then the function is linear and it will be a straight line.

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If f(x) = 5x2 + 3, find f(-2)<br> =
Brut [27]

Answer:To find this, all you have to do is plug in 3 where x is in the equation, which gives you this:

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8 0
2 years ago
Solve for x. Round to the nearest tenth.
skelet666 [1.2K]

Answer:

D. 14.1

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Use sin, opposite over hypotenuse.

sin67 = 13/X

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8 0
3 years ago
HELP....PLEASE,USE GEOMETRY!
liberstina [14]

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18\pi

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3 years ago
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The points represented by the (x, y) coordinate pairs all lie on line "k". These are the points: (1,3), (2, 1), (3,-1). (4.-3),
hammer [34]

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6 0
3 years ago
Rewrite as y−k=a(x−h)2 or x−h=a(y−k)2. Find the vertex, focus, and directrix.<br> y−3=(2−x)^2
Talja [164]

Given:

The given equation is

y-3=(2-x)^2

To find:

The vertex, focus, and directrix.

Solution:

The equation of a parabola is

y-k=a(x-h)^2     ...(i)

where, (h,k) is vertex, \left(h,k+\dfrac{1}{4a}\right) and directrix is y=k-\dfrac{1}{4a}

We have,

y-3=(2-x)^2

It can be written as

y-3=(-(x-2))^2

y-3=(x-2)^2    ...(ii)

On comparing (i) and (ii), we get

h=2,k=3,a=1

Vertex of the parabola is (2,3).

Focus=\left(2,3+\dfrac{1}{4(1)}\right)

Focus=\left(2,3+\dfrac{1}{4}\right)

Focus=\left(2,\dfrac{13}{4}\right)

Therefore, the focus of the parabola is \left(2,\dfrac{13}{4}\right).

Directrix of the parabola is

y=3-\dfrac{1}{4(1)}

y=3-\dfrac{1}{4}

y=\dfrac{11}{4}

Therefore, the directrix of the parabola is y=\dfrac{11}{4}.

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