The population mean annual salary for environmental compliance specialists is about $63,500. A random sample of 35 specialists i
s drawn from this population. What is the probability that the mean salary of the sample is less than $60,000? Assume σ = $6100
1 answer:
Answer:
0.003
Step-by-step explanation:
By formula we know that:
z (x) = (x - m) / [sd / sqrt (n)]
where x is the value we want to know (60,000), m is the mean (63500), sd is the standard deviation (6100) and n is the sample size (35).
Replacing we have:
z (60000) = (60000 - 63500) / [6100 / sqrt (35)]
z = -3.39
If we look in the normal distribution table (attached), we have that the probability is 0.0003.
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Then all the (x)'s should be 4 more than the original value
For example: (2,-3) <span>→ (6,-3)
Now since the Trapezoid was translated down 3,
Then all the (y)'s should be 3 less than the original value
For example: (2,-3) </span><span>→ (2,-6)
Now do this to all the Vertices
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