Answer:
GQ=25 units
Step-by-step explanation:
we know that
Point Q is the midpoint of GH
so
GH=GQ+QH and GQ=QH
GH=2GQ -------> equation A
we have
GH=5x-5
GQ=2x+3
substitute in the equation A and solve for x
5x-5=2(2x+3)
5x-5=4x+6
5x-4x=6+5
x=11
Find the length of GQ
GQ=2x+3
substitute the value of x
GQ=2(11)+3
GQ=25 units
Answer:
184 in.^2
Step-by-step explanation:
The cross section through the center of a sphere is a circle whose radius is equal to the radius of the sphere.
area of circle





surface area of sphere



Answer: i believe
that x does not have a value
Step-by-step explanation:"variable" or sometimes an "unknown"
Answer:
3 • (2xy - 7) • (xy + 2)
Step-by-step explanation:
(((2•3x2) • y2) - 9xy) - 42
6x2y2 - 9xy - 42 = 3 • (2x2y2 - 3xy - 14)
Answer: 4,032
Step-by-step explanation:
8,4 x 0,48 = 4,032