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SIZIF [17.4K]
3 years ago
7

Need help on these math questions. please and thank u

Mathematics
1 answer:
Svetach [21]3 years ago
4 0

9514 1404 393

Answer:

  a) x = -3

  b) y = (28/27)x -27

Step-by-step explanation:

a) College street has a slope of 0, so is a horizontal line. 2nd Ave is perpendicular, so is a vertical line, described by an equation of the form ...

  x = constant

For 2nd Ave to intersect the point (-3, 1), the constant must match that x-coordinate. The equation is ...

  x = -3

__

b) Since Ace Rd is perpendicular to Davidson St, its slope will be the opposite reciprocal of the slope of Davidson St. The slope of Ace Rd is ...

  m = -1/(-27/28) = 28/27

Using the point-slope equation for a line, we can model Ace Rd as ...

  y -y1 = m(x -x1)

  y -1 = (28/27)(x -27)

  y = (28/27)x -27

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In △ABC, ∠ABC = 60 degrees .
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A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.

A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is 180^{o}.

In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = 120^{o}. Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of 30^{o}.

Thus;

<ABP = 30^{o}

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Apply the <em>Sine rule</em> to determine the value of PB, such that;

\frac{a}{SinA} = \frac{b}{SinB}

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BP = \frac{8*Sin 30}{Sin 30}

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Therefore, the value of <u>PB</u> = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

#SPJ1

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