The answer is: the light rays refract toward a central axis.
Answer : (8,5)
Given
K(x) = ![8-\sqrt[3]{x}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7Bx%7D)
Now we plug in each point and check whether it satisfies our equation
(-64,12)
K(-64) = ![8-\sqrt[3]{-64}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B-64%7D)
= 12 so this point lie on graph
(125,3)
K(125) = ![8-\sqrt[3]{125}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B125%7D)
= 3 so this point lie on graph
(343,1)
K(343) = ![8-\sqrt[3]{343}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B343%7D)
= 1 so this point lie on graph
(8,5)
K(8) = ![8-\sqrt[3]{8}](https://tex.z-dn.net/?f=8-%5Csqrt%5B3%5D%7B8%7D)
= 6 so this point does not lie on graph because we got 6 instead of 5
Answer:
x1=-11
x2=3
(3,-11)
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Answer:
you need to tell us what error she made first then you would find another way to solve the problem and look at all the posiibiltys
Step-by-step explanation:
