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Sonja [21]
3 years ago
9

In a​ study, researchers wanted to measure the effect of alcohol on the hippocampal​ region, the portion of the brain responsibl

e for​ long-term memory​ storage, in adolescents. The researchers randomly selected 23 adolescents with alcohol use disorders to determine whether the hippocampal volumes in the alcoholic adolescents were less than the normal volume of 9.02 cm3. An analysis of the sample data revealed that the hippocampal volume is approximately normal with no outliers and x=8.16 cm3 and s=0.7 cm3. Conduct the appropriate test at the α=0.01 level of significance.
Mathematics
1 answer:
Anton [14]3 years ago
4 0

Answer:

We do not reject the Null Hypothesis

Step-by-step explanation:

From the question we are told that:

Sample size n=23

Population mean \mu=9.02cm^3

Sample mean \=x=8.16

Standard deviation \sigma=0.7cm^3

Significance level \alpha =0.01

Generally the Null and and alternative Hypothesis are as follows

 H_0:\mu=9.02cm^3

 H_a:\mu

Therefore t critical Value is

 t\ critical\ Value=(\alpha,df)

 t\ critical\ Value=(0.01,22)

Where

  df=n-1\\\\df=23-1=>22

Therefore

From t Table

 t value=-2.8

Generally the equation for Z Critical is mathematically given by

 t=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }

 t=\frac{8.16-9.02}{\frac{0.7}{\sqrt{23} } }

 t=-5.89

Therefore

Since the t test statistics is greater than the Critical value

Hence,we do not reject the Null Hypothesis

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maks197457 [2]

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Step-by-step explanation:

5 0
3 years ago
Which distribution is used to test the claim that women have a higher mean resting heart rate than men?
xeze [42]

This question is incomplete, the complete question is;

Assume that two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Which distribution is used to test the claim that women have a higher mean resting heart rate than men?

A.t

B.F

C.Normal

D. Chi-square

Answer:

A) t  test

Step-by-step explanation:

A t-test uses sample information to assess how plausible it is for the population means μ1​ and μ2​ to be equal.

The formula for a t-statistic for two population means (with two independent samples), with unknown population variances shows us how to calculate t-test with mean and standard deviation and it depends on the assumption of having an equal variance or not.

If the variances are assumed to be not equal,

he formula is:

t =  (bar X₁ - bar X₂) / √( s₁²/n₁ + s₂²/n₂ )

If the variances are assumed to be equal, the formula is:

t =  (bar X₁ - bar X₂) / √ (((n₁ - 1)s₁² + (n₂ - 1)s₂²) / (n₁ + n₂ - 2)) ( 1/n₁ + 1/n₂)

it called t-test for independent samples because the samples are not related to each other, in a way that the outcomes from one sample are unrelated from the other sample.

hence option A is correct. t test

4 0
3 years ago
What is the image of the point (-6,2) after a 90 degree counterclockwise rotation
Gala2k [10]
The answer is (-2, -6)
to rotate 90 degrees counterclockwise, you do (-y, x)
5 0
3 years ago
What is the approximate value for the modal daily sales?
Aleksandr [31]

Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

5 0
3 years ago
The teenage market is a market that is categorized in what way?
shepuryov [24]
The answer is option d.
<span>The teenage market is a market that is categorized by consumer way.
we can say this because consumer means what you use or what you like to you use. These days teenagers like to eat fast food and go out with friends to enjoy and eat. so if you market a fast food shop, it means you are looking at the consumer way. That is why d is the best option.</span>
7 0
3 years ago
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