Can someone help find x, y, and z

Mathematics

1 answer:

nalin [4]3 years ago

8 0

Answer:

Step-by-step explanation:

x^2=13^2-12^2

x^2=25

x=5

(sin90)/13=(sin(90-A))/5

sin(90-A)=5/13

90-A=arcsin(5/13)

A=90-arcsin(5/13)

tan(90-arcsin(5/13))=5/y

y=5/(tan(90-arcsin(5/13))

y=25/12

z^2=(25/12)^2+5^2

z=65/12

(x,y,z)=(5, 25/12, 65/12)

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