8y-6( add the variables together then add 8 to negative 14
Hey there!
To start, the mean of the answer is also known as the average value of a set of numbers. This is calculated by dividing the sum of the set by the total amount of numbers.
In this case the sum of all the numbers is 13 + 6 + 8 + 6 + 15 which is equal to 48.
Now, divide 48 by the total number of numbers in the set: 48/5 = 9.6
Your final answer should be 9.6, or you can leave it in fraction form as 48/5.
Hope this helps!
<h2><u>Solution 1</u> :</h2>
Cost of
pounds of gummy bears = $4.40
Cost of 1 pound of gummy bears :










Therefore, 1 pound of gummy bears = <u>$3.3</u>
<h2><u>Solution 2</u> : </h2>
Cost of 1 pound of gummy bears = $3.3
Money Daniel has = $1.00
Quantity of gummy bears he can afford :






Therefore, Daniel will be able to buy <u>0.30 pounds</u> of gummy bears from Jio.
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.

.

.

. The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same. In other words, we cannot add the square root of 4 to the square root of 5. They either both have to be 4 or they both have to be 5. So here's what we have thus far:

. We can add

and

to get

. That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.