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3 years ago

14

Deshawn makes jewelry from sea glass and sells it online. for every order he adds a 3.50 shipping fee to the price of the jewelr

y.
write an equation that represents the price with shipping y of jewelry with a price of x dollars.

Please Help

1 answer:

Stells [14]3 years ago

5 0

Answer:

This should be it

lmk if you have questions

y = x + 3.50.

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Write the equation in standard form for the circle x2+y2–36=0.

Marysya12 [62]

Answer:

x^2 + y^2 = 36

Step-by-step explanation:

Just add 36 to both sides. This is a circle with the center at the origin and radius 6.

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3 years ago

Find the domain and range of the exponential function h(x) = –343x.

Amanda [17]

The function is supposed to be;

h(x) = -343^(x)

Answer:

The domain will be a set of real numbers while the range will be y ≤ 0 and on the interval (-∞, 1)

As x is increasing, h is decreasing and as x is decreasing, h is increasing

Step-by-step explanation:

We are given the function as;

h(x) = -343^(x)

The formula is;

y = a^(x) since it's symmetrical to the x-axis

However in this case;

y = -a^(x)

Now, the domain is y and the range is a set of values of x.

I've attached a graph of this function drawn on desmos.

From the graph we can see that The domain will be a set of real numbers while the range will be on the interval (-∞, 1)

For a value of x = 0,we have;

h(0) = -343^(0)

h(0) = -343

When we increase the value of x to 3,we have;

h(3) = -343^(3)

h(3) = -40353607

When we decrease the value of x to -3, we have;

h(-3) = -343^(-3)

h(-3) = 0.00000002478

Thus, we can conclude that;

As x is increasing, h is decreasing and as x is decreasing, h is increasing

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2 years ago

Help me please tomorrow there is my exam

emmainna [20.7K]

Answer:

$\frac{2y^{3} }{x^{2} - y^{2} }$

2y^3 / x^2 - y^2

hope this helps and is right. p.s i really need brainliest :)

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2 years ago

What is the area of the triangle? 24,25,7<br>Pls pls helpp!!!!

Ksju [112]

Answer:

84

Step-by-step explanation:

A= 1/2• bh

A= 1/2•24(7)

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3 years ago

Read 2 more answers

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

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3 years ago