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sukhopar [10]
3 years ago
14

Deshawn makes jewelry from sea glass and sells it online. for every order he adds a 3.50 shipping fee to the price of the jewelr

y.
write an equation that represents the price with shipping y of jewelry with a price of x dollars.

Please Help​
Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer:

This should be it

lmk if you have questions

y = x + 3.50.

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Limit question: lim x--&gt;pi ((e^sinx)-1)/(x-pi)
aleksandr82 [10.1K]
\displaystyle\lim_{x\to\pi}\dfrac{e^{\sin x}-1}{x-\pi}

Notice that if f(x)=e^{\sin x}, then f(\pi)=e^{\sin\pi}=e^0=1. Recall the definition of the derivative of a function f(x) at a point x=c:

f'(c):=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}

So the value of this limit is exactly the value of the derivative of f(x)=e^{\sin x} at x=\pi.

You have

f'(x)=\cos x\,e^{\sin x}\implies f'(\pi)=\cos\pi\,e^{\sin\pi}=-1
4 0
3 years ago
What is the distance between -2 1/2, -5 3/4
Leviafan [203]

Answer:

Step-by-step explanation:

it's kinda confusing b/c of the minus signs.. huh...  but -5 is less than -2 sooo

start with

-2 1/2  - (-5 3/4 )

=5 3/4 - 2 1/2

=5 3/4 - 2 2/4

=23/4 - 10/4

=13/4

there you go...  :)

if you want it back in proper fractions

3 1/4

8 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
5. In one year, there were 125 major new automobile types available. If you look at the miles per gallon (MPG) for these vehicle
ziro4ka [17]

Answer:

The answer is "99.82% and 86.99%".

Step-by-step explanation:

In point a:

=P(X < 45)\\\\= P(Z < \frac{45-29.09}{5.46}) \\\\=P(Z < 2.9139)\\\\=0.9982\\\\=99.82\%

In point b:

=P(X >17)\\\\= P(Z > \frac{17-22.37}{4.77}) \\\\=P(Z > -1.1258)\\\\=0.8699\\\\=86.99\% \\\\

5 0
2 years ago
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