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fredd [130]
3 years ago
11

Get this post to 100 likes and ill give 5$ to the first 50th people who like it, (only cashapp or paypal)

Mathematics
1 answer:
andre [41]3 years ago
8 0

you've got 250 dollars just sitting around?

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I’m honestly done with math
rewona [7]

Answer:

15.

Step-by-step explanation:

8x - 10 = 110    (vertical angles are equal in measure).

8x - 10+ 10 = 110 + 10

8x = 120

x = 120 /8

x = 15.

3 0
3 years ago
2x-7y=12 for y answer please​
Marat540 [252]

Answer: If you want mx + b= y form and you want the y intercept, then the answer would be 2x/7 - 12/7 = y. The y intercept is b, so it is 12/7.

Step-by-step explanation: 2x - 7y = 12

Move -7y to the other side: 2x= 12 + 7y

Subtract 12 to the left side: 2x - 12 = 7y

Then divide 7 into everything: 2x/7 - 12/7 = 7y/7

The 7s in the right side cancel out, so the equation is now: 2x/7 - 12/7 = y

The y intercept is b, which is the second term in the equation, so the

Y Equals : 12/7

I hope this is what you are looking for!  

6 0
3 years ago
Read 2 more answers
Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
Which statement is true regarding the functions on the graph?
sergey [27]

Answer:

f(3) = g(3)

General Formulas and Concepts:

<u>Algebra I</u>

  • Reading a Coordinate Graph
  • Coordinates (x, y)
  • Solving systems of equations by graphing
  • Functions
  • Function Notation

Step-by-step explanation:

According to the graph, we see that both lines intersect at <em>x</em> = 3. Therefore, that means both lines at that <em>x</em> point will have the same <em>y</em> value. Both f(3) and g(3) would equal 6, leading us to the answer of f(3) = g(3).

7 0
3 years ago
Read 2 more answers
The graph of f(x) = x2 has been shifted into the form f(x) = (x − h)2 + k: a parabola with a vertex of 4, negative 2 What is the
katrin [286]

Answer:

k = -2

Step-by-step explanation:

f(x) = (x − h)² + k

(h, k) is the (x, y) coordinate of the vertex

For a vertex of (4, -2)

h = 4

k = -2

7 0
2 years ago
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