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3 years ago

Three decimals between 8.6 and 9.2?

Mathematics

2 answers:

charle [14.2K]3 years ago

6 0

Answer:

8.7, 8.9, 9.0

Step-by-step explanation:

nydimaria [60]3 years ago

4 0

Answer:

8.7, 8.9, & 9.1

Step-by-step explanation:

The decimal places go up by tens like all other numbers. Therefore, 8.7, 8.9, and 9.1 are all in between 8.6 and 9.2

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Bassima evaluated the expression below. 2 (12 minus 14) squared minus (negative 5) + 12 = 2 (negative 2) squared minus (negative

S_A_V [24]

Answer:

the answer is that Bassima evaluated -(-5) as 5.

Step-by-step explanation:

Hope it helps :)

Also srry for late response

5 0

3 years ago

Read 2 more answers

BRAINLIEST ASAP! PLEASE HELP ME :)

Margaret [11]

Answer:

$\large \boxed{\text{3.0 mi/h}}$

Step-by-step explanation:

Let x = the current of the river

Then 21 + x = the speed going downstream (with the current)

a nd 21 - x = the speed going upstream (against the current)

Distance = speed × time

d = st

t = d/s

Time going downstream = time going upstream

$\begin{array}{rcll}\dfrac{2.4}{21+ x}& = & \dfrac{1.8}{21 - x} &\\\\2.4& = &(21 + x) \dfrac{1.8}{21 - x} &\text{Multiplied each side by (21 + x)}\\\\2.4(21 - x)& = & 1.8(21 + x) &\text{Multiplied each side by (21 - x)}\\50.4 - 2.4x&=& 37.8 + 1.8x&\text{Removed parentheses}\\50.4 & = & 37.8 + 4.2x & \text{Added 2.4x to each side}\\\end{array}\\$

$\begin{array}{rcll}12.6 & = & 4.2x & \text{Subtracted 37.8 from each side}\\x & = &\dfrac{12.6}{4.2}&\text{Divided each side by 4.2}\\\\ & = &\mathbf{3.0}& \text{Simplified}\\\\\end{array}\\\text{The current is $\large \boxed{\textbf{3.0 mi/h}}$}$

Check:

$\begin{array}{rcl}\dfrac{2.4}{21+ 3}& = & \dfrac{1.8}{21 - 3}\\\\\dfrac{2.4}{24}& = & \dfrac{1.8}{18}\\\\0.10 & = & 0.10\\\end{array}$

4 0

3 years ago

Which graph represent the solution set of this inequality

VashaNatasha [74]

Hi!

First, let me explain that open circles mean that the answer starts after or before that number. So if the answer is q < 4, the answer would be C, and not B.

If the answer was q ≤ 4, the answer would be B, and not C.

I hope that makes sense. Now let's solve the inequality.

Remember that whatever we do to the inequality, we have to do it to both sides.

We need to isolate q on one side.
11q + 5 ≤ 49
Start by subtracting 5 from both sides.
11q + 5 - 5 ≤ 49 - 5
11q ≤ 44
Divide by 11 on both sides.
11q/11 ≤ 44/11
q ≤ 4

The answer is B.

Hope this helps! :)

3 0

3 years ago

What times what equals 68 ?

Anna71 [15]

34 x 2 = 68
17 x 4 = 68

3 0

4 years ago

Help with num 1 please.

KengaRu [80]

Answer:

(i) $\displaystyle y' = (6x - 1)ln(2x + 1) + \frac{2x(3x - 1)}{2x + 1}$

(ii) $\displaystyle y' = \frac{2x}{ln(x)} - \frac{x^2 + 2}{x(lnx)^2}$

(iii) $\displaystyle y' = \frac{e^x[xln(2x) + 1]}{x}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Exponential Differentiation

Logarithmic Differentiation

Step-by-step explanation:

(i)

Step 1: Define

Identify

$\displaystyle y = (3x^2 - x)ln(2x + 1)$

Step 2: Differentiate

Product Rule: $\displaystyle y' = (3x^2 - x)'ln(2x + 1) + (3x^2 - x)[ln(2x + 1)]'$
Basic Power Rule/Logarithmic Differentiation [Chain Rule]: $\displaystyle y' = (6x - 1)ln(2x + 1) + (3x^2 - x)\frac{1}{2x + 1}(2x + 1)'$
Basic Power Rule: $\displaystyle y' = (6x - 1)ln(2x + 1) + (3x^2 - x)\frac{2}{2x + 1}$
Simplify [Factor]: $\displaystyle y' = (6x - 1)ln(2x + 1) + \frac{2x(3x - 1)}{2x + 1}$

(ii)

Step 1: Define

Identify

$\displaystyle y = \frac{x^2 + 2}{lnx}$

Step 2: Differentiate

Quotient Rule: $\displaystyle y' = \frac{(x^2 + 2)'lnx - (x^2 + 2)(lnx)'}{(lnx)^2}$
Basic Power Rule/Logarithmic Differentiation: $\displaystyle y' = \frac{2xlnx - (x^2 + 2)\frac{1}{x}}{(lnx)^2}$
Rewrite: $\displaystyle y' = \frac{2xlnx}{(lnx)^2} - \frac{(x^2 + 2)\frac{1}{x}}{(lnx)^2}$
Simplify: $\displaystyle y' = \frac{2x}{ln(x)} - \frac{x^2 + 2}{x(lnx)^2}$

(iii)

Step 1: Define

Identify

$\displaystyle y = e^xln(2x)$

Step 2: Differentiate

Product Rule: $\displaystyle y' = (e^x)'ln(2x) + e^x[ln(2x)]'$
Exponential Differentiation/Logarithmic Differentiation [Chain Rule]: $\displaystyle y' = e^xln(2x) + e^x(\frac{1}{2x})(2x)'$
Basic Power Rule: $\displaystyle y' = e^xln(2x) + e^x(\frac{1}{2x})2$
Simplify: $\displaystyle y' = e^xln(2x) + \frac{e^x}{x}$
Rewrite: $\displaystyle y' = \frac{xe^xln(2x) + e^x}{x}$
Factor: $\displaystyle y' = \frac{e^x[xln(2x) + 1]}{x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

6 0

3 years ago