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3 years ago

Add my friend windows 86

Mathematics

1 answer:

emmainna [20.7K]3 years ago

7 0

Answer:

sexo

Step-by-step explanation:

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Solve the nonlinear system of equations

Kitty [74]

Answer:

There are no real solutions. The complex solutions are ...

(x, y) = (2.5-i√1.75, -2.5+i√1.75) or (2.5+i1.75, -2.5-i1.75)

Step-by-step explanation:

Subtract the first equation from the second.

y -y = (x^2 -6x +8) -(-x)

0 = x^2 -5x +8

Rewrite to facilitate completing the square:

x^2 -5x = -8

x^2 -5x +6.25 = -1.75 . . . . . add 6.25 to complete the square

(x -2.5)^2 = -1.75 . . . . . write as a square

x -2.5 = ±i√1.75 . . . . . . take the square root

x = 2.5 ± i√1.75 . . . . . . add 2.5; y is the opposite of this

Solutions are ...

x = 2.5 +i√1.75, y = -2.5 -i√1.75
x = 2.5 -i√1.75, y = -2.5 +i√1.75

_____

The graph shows the equations have no point of intersection, meaning there are no real solutions. The complex solutions are shown above.

3 0

3 years ago

Factor completely.

Zolol [24]

Answer:

B) 6(x-5) (x+5)

Step-by-step explanation:

Common factor.

6 ( ^2 − 25)

Use the sum-product pattern.

6 ( ^2+5−5−25).

Common factor from the two pairs.

6((+5)−5(+5)).

Rewrite in factored form.

6 ( − 5 ) ( + 5).

4 0

3 years ago

After Ronaldo Fourth of July party 2/3 of his cake is left. How much cake will be left if his cousin Max eats another 1/6 ? Simp

Zinaida [17]

2/3=4/6.
4/6-1/6=3/6=1/2

4 0

4 years ago

What is the slope and y-intercept?

allsm [11]

Answer:

7 is the y-intercept

slope is 2/1

Step-by-step explanation:

4 0

3 years ago

Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the

Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form $a\sin(x)+b\cos(x)$ . We want to express it as a sine term only by using the following formula $\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)$

The trick consists on find a number $\beta \in [0,2\pi]$ such that $\cos(\beta) = a, \sin(\beta)=b$ . But, note that since $\cos^2(\beta)+\sen^2(\beta)=1$ it is most likely that $a^2+b^2neq 1$ . Then, we will use the following equations:

$\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B$

Then, problem turns out to be

$a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta)$ ,

where $\beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})$

b) The amplitude is $\sqrt[]{15^2+4^2} = \sqrt[]{241}$ . Since $2\pi rad/s = 1 Hz$ the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

7 0

3 years ago

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