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ozzi
3 years ago
15

Add my friend windows 86

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

sexo

Step-by-step explanation:

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Solve the nonlinear system of equations
Kitty [74]

Answer:

  There are no real solutions. The complex solutions are ...

  (x, y) = (2.5-i√1.75, -2.5+i√1.75)  or  (2.5+i1.75, -2.5-i1.75)

Step-by-step explanation:

Subtract the first equation from the second.

  y -y = (x^2 -6x +8) -(-x)

  0 = x^2 -5x +8

Rewrite to facilitate completing the square:

  x^2 -5x = -8

  x^2 -5x +6.25 = -1.75 . . . . . add 6.25 to complete the square

  (x -2.5)^2 = -1.75 . . . . . write as a square

  x -2.5 = ±i√1.75 . . . . . . take the square root

  x = 2.5 ± i√1.75 . . . . . . add 2.5; y is the opposite of this

Solutions are ...

  • x = 2.5 +i√1.75, y = -2.5 -i√1.75
  • x = 2.5 -i√1.75, y = -2.5 +i√1.75

_____

The graph shows the equations have no point of intersection, meaning there are no real solutions. The complex solutions are shown above.

3 0
3 years ago
Factor completely.
Zolol [24]

Answer:

B) 6(x-5) (x+5)

Step-by-step explanation:

Common factor.

6 ( ^2 − 25)

Use the sum-product pattern.

6 ( ^2+5−5−25).

Common factor from the two pairs.

6((+5)−5(+5)).

Rewrite in factored form.

6 ( − 5 ) ( + 5).

4 0
3 years ago
After Ronaldo Fourth of July party 2/3 of his cake is left. How much cake will be left if his cousin Max eats another 1/6 ? Simp
Zinaida [17]
2/3=4/6.
4/6-1/6=3/6=1/2
4 0
4 years ago
What is the slope and y-intercept?
allsm [11]

Answer:

7 is the y-intercept

slope is 2/1

Step-by-step explanation:

4 0
3 years ago
Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the
Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form a\sin(x)+b\cos(x). We want to express it as a sine term only by using the following formula \sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)

The trick  consists on find a number \beta \in [0,2\pi] such that \cos(\beta) = a, \sin(\beta)=b . But, note that since \cos^2(\beta)+\sen^2(\beta)=1 it is most likely that a^2+b^2neq 1. Then, we will use the following equations:

\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B

Then, problem turns out to be

a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta),

where \beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})

b) The amplitude is \sqrt[]{15^2+4^2} = \sqrt[]{241}. Since 2\pi rad/s = 1 Hz the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

7 0
3 years ago
Read 2 more answers
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