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spayn [35]
3 years ago
12

Which equation is equivalent to y=2/3x-6

Mathematics
1 answer:
Anastaziya [24]3 years ago
6 0
D.2x-3y=18 thankssss
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Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.
saw5 [17]

Car 1: It is an exponential function that is given as P = 18,500 (0.9595)ⁿ and the price after 10 years is $12,235.5.

Car 2: It is a linear function that is given as 2000x + 3y = 55500 and the price after 10 years is $11,833.33.

And Yes, there is a significant difference.

<h3>What is a function?</h3>

A function is a statement, rule, or law that establishes the connection between two variables. In mathematics, functions are everywhere and are necessary for constructing physical connections.

Baxter is thinking about buying a car. The table below shows the projected value of two different cars for three years.

Car 1 (value in dollars)

Year 1: 18,500

Year 2: 17,390

Year 3: 16,346.60

Car 2 (value in dollars)

Year 1: 18,500

Year 2: 17,500

Year 3: 16,500

The exponential function describes car 1.

Then the function will be

\rm P = 18500\times (0.95995)^n

The linear function describes car 2.

\rm y \ - \ 18500 = \dfrac{-2000}{3}(x - 0)\\\\\\3y - 55500 = -2000x\\\\\\2000x +3y = 55500

Then the value of the car 1 after 10 years will be

\rm P = 18500\times (0.95995)^{10}\\\\\\P = \$ \ 12,235.5

Then the value of the car 2 after 10 years will be

\rm 2000 \times 10 +3y = 55500\\\\y =  \$ \ 11,833.33

Yes, there is a significant difference.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

5 0
2 years ago
Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
  • (1 - sinθ)² / cos²θ

<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
  • secθ - tanθ
<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
  • (1 - cosθ)²/sin²θ

<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
  • 1/sinθ - cosθ / sinθ =
  • cosecθ - cotθ

<u>Sum of the results:</u>

  • cosecθ + cotθ + cosecθ - cotθ =
  • 2cosecθ
4 0
3 years ago
Read 2 more answers
Big trouble what is 99-30
katovenus [111]
I think it is 69 the rat
6 0
3 years ago
Multiply &amp; simplify: (2a - 3)(2a + 1)
RoseWind [281]
I hope this helps you



2a.2a+1.2a-3.2a-3.1


4a^2+2a-6a-3


4a^2-4a-3
3 0
3 years ago
G(x)= 3x − 3; Find g(−6)
Irina18 [472]
<span>g(x)= 3x − 3
</span><span>g(−6)

g(-6) = 3(-6) - 3
g(-6) = -18 - 3
g(-6) = -21

The answer is -21.</span>
4 0
3 years ago
Read 2 more answers
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