Answer:
The input for the method is a continuous function f, an interval [a, b], and the function values f(a) and f(b). The function values are of opposite sign (there is at least one zero crossing within the interval). Each iteration performs these steps: Calculate c, the midpoint of the interval, c = a + b2.
Step-by-step explanation:
trust
This is an exponential growth/decay problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case:
F=I(1.03)^t and they just want to know when F=2I so
2=1.03^t take natural log of both sides...
ln2=t*ln1.03
t=ln2/(ln1.03)
t≈23.45
So it will take approximately 23.45 years for the population to double..
1990+23.45=2013.45
So during the year of 2013 the population will have double from its 1990 level.
The computer regression output includes the R-squared values, and adjusted R-squared values as well as other important values
a) The equation of the least-squares regression line is 
b) The correlation coefficient for the sample is approximately 0.351
c) The slope gives the increase in the attendance per increase in wins
Reasons:
a) From the computer regression output, we have;
The y-intercept and the slope are given in the <em>Coef</em> column
The y-intercept = 10835
The slope = 235
The equation of the least-squares regression line is therefore

b) The square of the correlation coefficient, is given in the table as R-sq = 12.29% = 0.1229
Therefore, the correlation coefficient, r = √(0.1229) ≈ 0.351
The correlation coefficient for the sample, r ≈ <u>0.351</u>
c) The slope of the least squares regression line indicates that as the number of attending increases by 235 for each increase in wins
Learn more here:
brainly.com/question/2456202
Answer:
the answer is inverse operations