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Serggg [28]
3 years ago
10

Can anyone help pls it's hard

Mathematics
1 answer:
Pie3 years ago
8 0

Answer:

(A\cap B)\cap U

Step-by-step explanation:

"And" indicates taking the <u>intersection</u> of two sets.

You want numbers that are in all three sets: multiples of 5, multiples of 2, and all 4-digit numbers.

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Sammy has a rectangular doormat on her porch. The mat is \dfrac45\text{ m} 5 4 ​ mstart fraction, 4, divided by, 5, end fraction
Otrada [13]

Answer:

Area of the rectangular doormat = 2/5 m²

Step-by-step explanation:

Length of the rectangular doormat = 4/5m

Width of the rectangular doormat = 1/2m

What is the area of the doormat?

Area of a rectangle = length × width

= 4/5m × 1/2m

= (4×1) / (5×2)

= 4 / 10

= 2/5 m²

Area of the rectangular doormat = 2/5 m²

6 0
3 years ago
Need some help with table 2.Fill up tables of proportional relationships with missing Values.
schepotkina [342]

Proportional Relationships

If the variables x and y are in a proportional relationship, then:

y = kx

Where k is the constant of proportionality that can be found as follows:

k=\frac{y}{x}

If we are given a pair of values (x, y), we can find the value of k and use it to fill the rest of the table.

For example, Table 1 relates the cost y of x pounds of some items. We are given the pair (2, 2.50). We can calculate the value of k:

k=\frac{2.50}{2}=1.25

Now, for each value of x, multiply by this factor and get the value of y. For example, for x = 3:

y = 1.25 * 3 = 3.75

This value is also given and verifies the correct proportion obtained above.

For x = 4:

y = 1.25 * 4 = 5

For x = 7:

y = 1.25 * 7 = 8.75

For x = 10:

y = 1.25 * 10 = 12.50

Now for table 2, we are given the pair (3, 4.5) which gives us the value of k:

k=\frac{4.5}{3}=1.5

Apply this constant for the rest of the table.

For x = 4:

y = 1.5 * 4 = 6

For x = 5:

y = 1.5 * 5 = 7.50

For x = 8:

y = 1.5 * 8 = 12

The last column doesn't give us the value of x but the value of y, so we need to solve for x:

y=k\cdot x\text{  }=>\text{ }x=\frac{y}{k}

For y = 15:

x=\frac{15}{1.5}=10

5 0
11 months ago
Easiest way to solve this?
ale4655 [162]

Answer:

add \: all \: and \: divide \: it \: by \: 4 \\  (4 + 6 + 6 + 2) \div 4 \\ 18 \div 4 \\   4.5

6 0
2 years ago
Read 2 more answers
The given figure is a regular hexagon with side length 12 and radius 10. Find its area.
Strike441 [17]

Answer:

if i was to guess it would be 96 or 120 this one got me stumped also

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates of
sukhopar [10]

Answer:

a) The probability is 0.04

b) The probability is 0.36

c) The pprobability is 0,25

d) The probability is 0.09

Step-by-step explanation:

Lets calculate areas:

the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.

a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04

b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.

c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25

d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.

6 0
3 years ago
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