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olga_2 [115]
2 years ago
7

A.(3,7) is a solution to the linear system.

Mathematics
1 answer:
uysha [10]2 years ago
8 0

Answer:

y = 2x + 1 --> linear

y = -4x + 7 --> non-linear

Not a solution for a linear system.

Step-by-step explanation:

for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:

7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.

for (b), we have to substitute our values again. You get:

7 = -4x3 + 7, which is

7 = -12+7, which is not true. So, (b) is not linear.

This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Rom4ik [11]

Answer:

x ≥ −5 and x < 4

Step-by-step explanation:

-4x + 1 ≤ 21 and 5x + 2 <  22

5x + 2 < 22 =<u> x < 4</u>

We can plug it in: 5 x 3 + 2 < 22 = <u>17 < 22</u>

-4x + 1 ≤ 21 = x= -5 and lower

Plug it in: -4 x -5 + 1 ≤ 21 = 21 ≤ 21 = <u>x ≥−5</u>

So both answers would be:

x ≥−5 for -4x + 1 ≥ 21

x < 4 for 5x + 2 <  22

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3 years ago
Which type of transformation is shown in the graph?
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3 years ago
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3 years ago
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15. Jim had 103 red and blue marbles. After giving of his blue marbles and 15 of his red marbles
sesenic [268]

This question above is incomplete

Complete Question

Jim had 103 red and blue marbles. After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles. How many blue marbles did he have originally?

Answer:

70 Blue marbles

Step-by-step explanation:

Let red marbles = R

Blue marbles = B

Step 1

Jim had 103 red and blue marbles.

R + B = 103.......Equation 1

R = 103 - B

Step 2

After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles

2/5 of B to Samantha

Jim has = B - 2/5B = 3/5B left

He also gave 15 red marbles to Samantha

= R - 15

The ratio of what Jim has left

= Red: Blue

= 3:7

= 3/7

Hence,

R - 15/(3/5)B = 3/7

Cross Multiply

7(R - 15) = 3(3/5B)

7R - 105 = 3(3B/5)

7R - 105 = 9B/5

Cross Multiply

5(7R - 105) = 9B

35R - 525 = 9B............ Equation 2

From Equation 1, we substitute 103 - B for R in Equation 2

35(103 - B) - 525 = 9B

3605 - 35B - 525 = 9B

Collect like terms

3605 - 525 = 9B + 35B

3080 = 44B

B = 3080/44

B = 70

Therefore, Jim originally had 70 Blue marbles.

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3 years ago
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