All categories

2 years ago

A.(3,7) is a solution to the linear system.

Mathematics

1 answer:

uysha [10]2 years ago

8 0

Answer:

y = 2x + 1 --> linear

y = -4x + 7 --> non-linear

Not a solution for a linear system.

Step-by-step explanation:

for (a), y = 2x+1, substitute the x and y values. keep in mind, that in a linear pair, (x, y). So, for the first equation you get:

7 = 2x3 + 1. This is correct, because 6 + 1 is 7. Therefore, (a) is linear.

for (b), we have to substitute our values again. You get:

7 = -4x3 + 7, which is

7 = -12+7, which is not true. So, (b) is not linear.

This means that for the linear pair (3, 7), it does not satisfy both equations, which means that it is not a solution for the linear system.

You might be interested in

A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.

Kobotan [32]

Answer:

The numbers are

$-2+3\sqrt{5}$ and $3\sqrt{5}$

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

$x=y-2$

$y=x+2$ ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

$4y+x^2=49$ ----> equation B

substitute equation A in equation B

$4(x+2)+x^2=49$

solve for x

$x^2+4x-41=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+4x-41=0$

$a=1\\b=4\\c=-41$

substitute in the formula

$x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}$

$x=\frac{-4\pm\sqrt{180}} {2}$

$x=\frac{-4\pm6\sqrt{5}} {2}$

$x=-2\pm3\sqrt{5}$

The positive real number is

$x=-2+3\sqrt{5}$

Find the value of y

$y=x+2$

$y=-2+3\sqrt{5}+2$

$y=3\sqrt{5}$

6 0

4 years ago

3. Find the value of x in the diagram below X 6 cm 5 4 cm 3 cm R

vazorg [7]

Answer:

4cm is the correct answer

8 0

3 years ago

Find the area between y=x^3 and y=x at [-1,1]

abruzzese [7]

Answer:

Step-by-step explanation:

$\int\limits^1_1 x^3 \, dx$ - $\int\limits^1_1 {x} \, dx$

Limits should be -1 to 1, its the integral of x^3 from -1 to 1 minus the integral of x from -1 to 1.

0-0 = 0

8 0

3 years ago

Read 2 more answers

Perfect adjective word chain

Charra [1.4K]

Answer:

Tall, light, test, treat.

I think this ans may help you

6 0

3 years ago

You are interested in determining which of two brands of batteries, brand A and brand B, lasts longer under differing conditions

kirza4 [7]

The flashlights should be the same for both branches. If one battery last longer than the other maybe that is because of how each flashlight use the energy of them. You can try, for example, mxing the flashlights so that 50 of each kind are fitted with each of the brands.

Another problem is that you cant meassure correctly the lifetime of a battery if it lasts longer than the 72 hours you are using it.

Also, you might want to study more than the mean lifetime. You can try finding the standard deviation of each sample for example so that you can see if there is a branch that suffer more about bad conditions of use and is less consistent providing a good preformance.

6 0

3 years ago