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3 years ago

Find the odds for and the odds against the event rolling a fair die and getting a 2, a 6, a 5 or a 1,

Mathematics

1 answer:

Archy [21]3 years ago

8 0

Answer:

2/3

Step-by-step explanation:

If the dice has six sides then it would be 4/6 because there's four numbers out of 6 and if you simplify it then it would be 2/3.

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What is the estimate of 119÷23.3

Crank

Your answer would be 5.10... Hope this helps :)

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3 years ago

HELP PLS ASAP

Ainat [17]

Answer:

1subtraction 2division

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3 years ago

Read 2 more answers

I just need the answers for questions 9 and 10

OverLord2011 [107]

Hello. To answer this questions, we need to remember some properties about fractions and equivalences.

Starting by the question 9:

Call the population 5 years ago by P. If the population has decreased 12000 in these 5 years and this represents a decrease of 3%, so it means the new population is 0.97P.

With this, we can make the following equation:

P - 12000 = 0.97P

Subtract 0.97P and sum 12000 in both sides of the equation

0.03P = 12000

Divide both sides of the equation by a factor of 0.03

P = 3600000

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1 year ago

What is the answer 3/4x1/2x2+2/3-3.4?

seropon [69]

Answer:

-1.98333333

Step-by-step explanation:

don't really know how to explain

7 0

3 years ago

Read 2 more answers

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

Hence, (-1,5) is on the graph

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

(1,0) is not on the graph because g(x) is not equal to 0

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

Hence, $(3, \frac{1}{125})$ is on the graph

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

Hence, $(-2, \frac{1}{25})$ is not on the graph

8 0

3 years ago