Fatima opened a savings account with $7,500. She decided to deposit that same amount semiannually. This account earns 3.975% int
1 answer:
Answer:
A = $11117.25
Step-by-step explanation:
Given the following data;
Principal = $7,500
Interest rate = 3.975% = 3.975/100 = 0.03975
Number of times, n = 2
Time, t = 10 years
To find the future value, we would use the compound interest formula;
Where;
A is the future value.
P is the principal or starting amount.
r is annual interest rate.
n is the number of times the interest is compounded in a year.
t is the number of years for the compound interest.
Substituting into the equation, we have;
A = $11117.25
You might be interested in
We want to find 
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
Thus,
Answer: A)
Answer:
Part 1)
Part 2)
Step-by-step explanation:
The picture of the question in the attached figure
Part 1
Find the length side AB
we know that
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
solve for AB
Part 2
Find the length side AC
we know that
----> by TOA (opposite side divided by the adjacent side)
substitute the given values
solve for AC
The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t
Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
#SPJ1