All categories

3 years ago

PLEASE HELP FAST

Mathematics

2 answers:

Minchanka [31]3 years ago

8 0

Answer:

candy bars = a

cupcakes = b

a=1.5$

b=2.25$

Step-by-step explanation:

candy bars = a

cupcakes = b

1)5a+2b = 12

2)3a + 3b = 11.25

We can understand

3a + 3b = 3(a+b)= 11.25

a+b = 11.25÷3 = 3.75

from No.2 equation.

than we do

(5a+2b) - 2(a+b)

and we got 3a

12 - 7.5 = 4.5 = 3a

a=1.5$

b=2.25$

Ne4ueva [31]3 years ago

3 0

Answer:

$23.25

Step-by-step explanation:

12+11.25

You might be interested in

What is the interquartile range of the following data set? 3,8, 14, 19, 22, 29, 33, 37, 43, 49. A. 26 B. 23 C. 19 D. 18

Fynjy0 [20]

Answer:

I think the answer is B.23

8 0

3 years ago

Which statement is always true?

kykrilka [37]

So the answer is that the negative export cannot be part of an expressions numerator here is a website that can help you know or explain more my my answer hope this helped https://www.purplemath.com/modules/exponent2.htm or this website

7 0

4 years ago

PLZ HELP ME If m<7=62 find m<1.

dsp73

Answer:

m<1 =118 ~trust me I just finished this section

3 0

3 years ago

According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating

Natali [406]

Answer:

a) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565$

The degrees of freedom for this sample size are:

$df=n-1=65-1=64$

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Critical value approach

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0

3 years ago

If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Fed [463]

Answer:

$\bold{(f+g)(x)=2x^2+\frac32x-5}$

Step-by-step explanation:

$f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5$

5 0

3 years ago