Hello There!
It would be 9(3w + 4) (3w + 4)
Hope This Helps You!
Good Luck :)
- Hannah ❤
Hey!
We can use long division to solve this,
Let's write it.

Then, divide

by

to get

.

Multiply the quotient by the divisor...

Subtract

from

.

As you can see, our answer using long division would be 3 with a remainder of 4.
Thanks!
-TetraFish
Answer:
20$ each visit
Step-by-step explanation
Divide 40 by 2 for her 2 visits to the bank

<em>Final Answer: </em>
Answer:
the answer is b between 6 and 7
Step-by-step explanation:
i say this because the square root of 41 is 6.4031.
6.4031 is in between 6 and 7.
hope this helps :)
The correct question is
<span>The product of two consecutive positive integers is
11 more than their sum. find the integers.
Let
x-------> the first </span>positive integer
x+1-----> the second consecutive positive integer
we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
x²-x-12=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution is
x=4
therefore
the numbers are
x=4
x+1=5
the answer isthe numbers are 4 and 5