It is rather obvious that we will have to deal with a trigonometric function. Let us see... the first hint is that a function is not defined somewhere. cos and sin are defined for all real numbers... what about tan though? Well, as we approach pi/2, tan becomes larger and larger and it is not defined at pi/2. Given that the tan function has a period of pi (cos and sin have a period of 2pi), this function is the right candidate. Since it is periodic and it is not defined at pi/2, it cannot be defined at any x=pi/2+-npi (if it was defined for some n, then it would have the same value at pi/2 due to periodicity). Hence, a function that works is tanx, or 2*tanx or tanx+6.
Answer:
. 2) It’s positive only if the first integer is greater
Answer:
d. m<ABD = 50°, m<GBC = 47°, m<EBC = 50°, and m<DBG = 83°
Step-by-step explanation:
m<ABF = 47° (given)
m<FBE = 83°
✍️m<ABD + m<ABF + m<FBE = 180° (angles on straight line)
m<ABD + 47° + 83° = 180° (substitution)
m<ABD + 130° = 180°
Subtract 130 from each side
m<ABD = 180° - 130°
✅m<ABD = 50°
✍️m<GBC = m<ABF (vertical angles)
✅m<GBC = 47° (Substitution)
✍️m<EBC = m<ABD (Vertical angles)
✅m<EBC = 50° (substitution)
✍️m<DBG = m<FBE (vertical angles)
✅m<DBG = 83° (Substitution)
Answer:
The correct answer is D
Step-by-step explanation:
From the problem :
In multiplying expressions with the same bases, the exponent will be added accordingly.
For example :
the exponent of a are m and n, and the product will be a raised to the sum of m and n.
Applying this to the problem, we have :
The answer is d. 6^-1
