- <em><u>Answer:</u></em>
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Step-by-step explanation:
Answer:
D. f(x) = -6x^3 -5x^2 +21x
Step-by-step explanation:
The given zeros mean the function has factors ...
(x -(-7/3))(x -3/2)(x -0)
Multiplying by 6, we can write this as ...
(3x +7)(2x -3)(x) = 6x^3 +5x^2 -21x
And multiplying by -1 gives ...
-6x^3 -5x^2 +21x . . . . . matches choice D
__
<em>Additional comment</em>
The product of factors will be zero when f(x) = 0. This means we can multiply or divide by any convenient factor and the product will remain zero. Effectively, we have multiplied our original factorization by -6 to make the expression match one of the given forms. When we write this final expression as the function f(x), it remains true that the given zeros are zeros (x-intercepts) of f(x).
If f(x) = x^2
Then g(x) goes under the 3 transformations given...,
; Reflection on the x-axis...; -f(x)
; 3 units to the left...., -f(x + 3)
; 7 units up..., -f(x + 3) + 7
Then for....,g(x) = -f(x + 3) + 7
Where the function is going to be...
; g(x) = -(x + 3)^2 + 7
; g(x) = -(x^2 + 6x + 9) + 7
; g(x) = -x^2 - 6x - 9 + 7
;Hence the function of g(x) after all those transformations
g(x) = -x^2 - 6x - 2
Answer:
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