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3 years ago

3 1/9+2 1/4= what is the answer

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:
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Step-by-step explanation:

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What is -5x - 3y = 21 in slope-intercept form?

djyliett [7]

Answer:

$\displaystyle y = -1\frac{2}{3}x -7$

Step-by-step explanation:

−5x - 3y = 21

+ 5x + 5x

__________

$\displaystyle \frac{-3y}{-3} = \frac{5x + 21}{-3} \\ \\ y = -1\frac{2}{3}x - 7$

I am joyous to assist you anytime.

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4 years ago

Find the ratio in the lowest terms of length to width for a rectangle with length 4 and width 2.

Gekata [30.6K]

4:2 = 2:1

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3 years ago

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10 PTS! 5 STAR RATING! THANKS ON QUESTION/PROFILE! FIRST TO ANSWER ALL 5 GETS BRAINLIEST!

Stells [14]

1) x = - 4 and y = 8
answer is d. last choice

2) x = 16 y =20
answer is d. last choice

3) x - 6y = -24
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answer is B. second choice

4) 4.75k + 2.25p = 22
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4 0

4 years ago

Read 2 more answers

The matrix below represents a system of equations.

noname [10]

Answer:

The first choice: $a = 1$ , $b = -1$ , and $c = 2$ .

Step-by-step explanation:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 1 & -1 & -2 \cr 1 & 0 & -3 & -5\end{array} \right]$ .

Add the first row to the second row to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 2 + 1 & (-1) + 1 & 1 + (-1) & 5 + (-2) \cr 1 & 0 & - 3& -5\end{array} \right]$ .

Simplify that matrix to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 3 & 0 & 0 & 3\cr 1 & 0 & -3 & -5\end{array} \right]$ .

Divide the second row by $3$ :

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 & 0 & -3& -5\end{array} \right]$ .

Hence, $a = 1$ .

Subtract the current row two from row three:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 1 - 1 & 0 & -3 & (-5)- 1 \end{array} \right]$ .

Simplify that matrix to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & -3 & -6 \end{array} \right]$ .

Invert the signs in the third row and divide it by $3$ to obtain:

$\left[ \begin{array}{ccc|c} 2 & -1 & 1 & 5 \cr 1 & 0 & 0 & 1\cr 0 & 0 & 1 & 2 \end{array} \right]$ .

Hence, $c = 2$ .

Subtract two times the current second row from the first row to obtain:

$\left[ \begin{array}{ccc|c} 2 - (2 \times 1) & -1 & 1 & 5 - 2\times 1\cr 1 & 0 & 0 & 1\cr 0 & 0&1 & 2 \end{array} \right]$ .

That simplifies to

$\left[ \begin{array}{ccc|c} 0 & -1 & 1 & 3\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Subtract the current third row from the first row to obtain:

$\left[ \begin{array}{ccc|c} 0 & -1 & 1-1 & 3-2\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

That simplifies to

$\left[ \begin{array}{ccc|c} 0 & -1 & 0& 1\cr 1 & 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Invert the signs in the first row to obtain:

$\left[ \begin{array}{ccc|c} 0 & 1 & 0& -1\cr 1& 0 & 0 & 1\cr 0 & 0 & 1& 2\end{array} \right]$ .

Hence, $b = -1$ .

$\left[ \begin{array}{ccc|c}1& 0 & 0 & 1 \cr0 & 1 & 0& -1 \cr 0 & 0 & 1& 2\end{array} \right]$ .

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4 years ago

Identify the maximum or minimum value and the domain and range of the graph of the function y = 2(x + 2)^2 - 3

enyata [817]

y = 2(x + 2)^2 - 3 has the form y = a(x-h)^2 + k.

Here, a=2, h=-2 and k=-3.

This is a quadratic function. Its graph is a vertical one which opens up (we know that because a = 2 is positive). Its vertex is (-2, -3). Because the graph opens up, (-2, -3) represents the minimum of this function.

The domain of any and all polynomial(s) includes "all real numbers."
The range is the set of possible outputs (y-values) and is (-3, infinity).

8 0

3 years ago