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3 years ago

8

John has 12 marbles of different colors, including one red, one green, and one blue marble. in how many ways can he choose 4 mar

bles, if exactly one of the chosen marbles is red, green, or blue?

2 answers:

Svetach [21]3 years ago

8 0

Answer:

252

Step-by-step explanation:

AoPs

Savatey [412]3 years ago

7 0

3 ways (uncertain)
1 red or blue or green + 3 other colours

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The diagram shows a sector of a circle radius 10cm

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Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

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2 years ago

Please help and choose letter choice

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The correct answer is a

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3 years ago

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Which equation represents the line passing through the points (4, −1) and (1, 0)? Select one: A. x + 3y = 1 B. 3x + y = 1 C. x −

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

Gradient of a line =( y2 - y1)/x2 - x1

From the question, x1=4,y1=-1,x2=1,y2=0.

Therefore, substitute for these values in the above formula

m = 0-(-1)/1-4

= 0+1/-3

= -1/3.

Therefore, y-y1/x-x1 = -1/3

y - y1 = -1/3(x - x1)

y - (-1) = -(x-x1)/3

y+1 = - (x - 4)/3

Multiply through by 3

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3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

<h3>1)</h3>

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

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3 years ago

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Answer:

2.4x = 1.2x + 15

13

Step-by-step explanation:

just did it

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3 years ago

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