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larisa86 [58]
3 years ago
9

The circumference of the

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

To the nearest inch it'll be

d×3.14=63

= 20 inches

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Find the value of x that will make A||B 4x 3x+10 x=
Ede4ka [16]

Answer:

4x 3x+10 x= 10

Step-by-step explanation:

3 0
3 years ago
What is the equation of the translated function?
Musya8 [376]
For this case the main function is:
 f (x) = x ^ 2
 We are going to apply the following transformations:

 Vertical translations
 Suppose that k> 0:
 To graph y = f (x) + k, move the graph of k units up.
 We have then:
 f (x) = x ^ 2 + 5

 Horizontal translations
 Suppose that h> 0
 To graph y = f (x + h), move the graph of h units to the left.
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3 0
3 years ago
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What is the probability that a point chosen at random in the triangle is also in the blue square?
matrenka [14]

The <u>probability</u> that a point <u>chosen at random</u> in the triangle is also in the blue square can be calculated using <u>geometrical definition of the probability</u>:

Pr=\dfrac{\text{desired area}}{\text{total area}}.

1. Find the total area of the triangle:

A_{total}=\dfrac{1}{2}\cdot 6\cdot 9=27\ in^2.

2. Find the desired area of the square:

A_{desired}=3\cdot 3=9\ in^2.

Then the probability is

Pr=\dfrac{9}{27}=\dfrac{1}{3}.

Answer: correct choice is B

8 0
3 years ago
Suppose we are testing people to see if the rate of use of seat belts has changed from a previous value of 88%. Suppose that in
Andreas93 [3]

Answer:

a) We would expect to see 500*0.88=440

b) z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=450 represent the people that have the seat belt fastened

\hat p=\frac{450}{500}=0.9 estimated proportion of people that have the seat belt fastened

p_o=0.88 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  Part aWe would expect to see 500*0.88=440Part bConcepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion changes fro m 0.88.:  Null hypothesis:[tex]p=0.88  

Alternative hypothesis:p \neq 0.88  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.9 -0.88}{\sqrt{\frac{0.88(1-0.88)}{500}}}=1.376  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.376)=0.167  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion is not significant different from 0.9.

The p value is a criterion to decide if we reject or not the null hypothesis, when p_v we reject the null hypothesis in other case we FAIL to reject the null hypothesis. And represent the "probability of obtaining the observed results of a test, assuming that the null hypothesis is correct".  

8 0
3 years ago
jane lives 1 3/8 miles from the airport. She drove from her house to the airport and back 2 times. How far did Jane drive? Move
Ket [755]

Answer:

5\frac{1}{2}\ mi

Step-by-step explanation:

we know that

1\frac{3}{8}\ mi=\frac{1*8+3}{8}=\frac{11}{8}\ mi

She drove from her house to the airport and back 2 times

so

Multiply the distance from her house to the airport by 4

(4)*\frac{11}{8}=\frac{11}{2}=5\frac{1}{2}\ mi

4 0
3 years ago
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