It would be helpful if you attached the table to solve this question
Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy
<h3>What is a
quadrilateral?</h3>
A quadrilateral is a polygon that has four sides and four angles. Types of quadrilateral are<em> square, kite, trapezoid, rectangle, rhombus </em>and so on.
A quadrilateral hierarchy is a graphical way of representing the different types of quadrilaterals.
Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy
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C) $694.25
Why?
Because you want to times the interest by 2 (1 is for one year but u want to find the amount after two years) then you multiply the amount given to each bank separately so:
400*0.07 (7% which is 7/100) = 28
250*0.065 (6.5% which is 65/1000) = 16.25
Then u add the interests together:
28+16.25 = 44.25
Finally you add that to the amount you started with:
$650+$44.25= $694.25
Answer:
a. 1
b. 5
Step-by-step explanation:
<h3>a.</h3>
Ordered pairs are (x, f(x)). You want f(2), so you look for an ordered pair that lists 2 as the first number. That one is (2, 1). This means f(2) = 1.
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<h3>b.</h3>
f(2) is plotted as the point (2, f(2)). That is, the x-coordinate of the point will be 2. The point that has x-coordinate 2 is (2, 5).
As above, this means f(2) = 5.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²