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ryzh [129]
3 years ago
10

I need help i don understand i got b but it said it was wrong .

Mathematics
2 answers:
Thepotemich [5.8K]3 years ago
4 0

Answer:

b is 135 and c is 45.................thanks

Vilka [71]3 years ago
3 0

Answer:

b=135\\c=45

Step-by-step explanation:

The angle that measures 135 degrees and angle b are opposite angles. Opposite angles are congruent. Therefore, angle b=135.

b=135

A straight line has an angle measure of 180 degrees. This means that 135+c would equal 180 degrees.

135+c=180

Subtract both sides by 135

135+c-135=180-135\\c=45

I hope this helps!

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PLS HELP ME & EXPLAIN ANSWER <3
defon

Answer:

  e.  10√30

Step-by-step explanation:

In this right triangle geometry, all of the right triangles are similar. This means that the ratio of long side to hypotenuse is the same for all triangles:

  x/(10+50) = 50/x

Multiplying by 60x, we have ...

  x^2 = 3000

  x = 10√30 . . . . . take the square root. Matches choice E.

_____

<em>Comment on estimating</em>

You're looking for x. Examining the figure, you see that x is the long side of the triangle with hypotenuse 10+50=60, so it will be shorter than that value. x is also the hypotenuse of the triangle with long side 50. So, x will be longer than 50.

The only answer choice with a value between 50 and 60 is choice E.

You don't even need to know how to find x. You only need to know that the hypotenuse is the longest side in a right triangle.

5 0
4 years ago
Find three consecutive numbers whose sum is 84
8_murik_8 [283]

Answer:

three  consecutive numbers that add up to 84 are 27,28 and 29

Step-by-step explanation:

27+28=55

55+29-=84

8 0
3 years ago
Find the maximum rate of change of f at the given point and the direction in which it occurs. f(x, y) = 2 sin(xy), (0, 5)
andrew-mc [135]

Answer:

<h2>10</h2>

Step-by-step explanation:

Given the function f(x, y) = 2 sin(xy) at (0,5), the maximum rate of change of the function at that point will occur in the direction \nabla f(0,5)

\nabla f(x, y) = \frac{\delta(2sin(xy)) }{\delta x} i + \frac{\delta(2sin(xy)) }{\delta y} j\\\\\nabla f(x, y) = 2ycos(xy)i + 2xcos(xy)j\\\\\nabla f(0, 5) =  2(5)cos(0*5)i + 2(0)cos(0*5)j\\\\\nabla f(0, 5) = 10cos0i+ 0j\\\\\nabla f(0, 5) = 10i+0j\\\\||\nabla f(0, 5)|| = \sqrt{10^2+0^2} \\\\||\nabla f(0, 5)||  = \sqrt{100} = 10

Hence, the magnitude of the maximum rate of the function at the point (0, 5) is 10

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