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Taya2010 [7]
3 years ago
12

What the value of x. Please

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

x = 11.7

Step-by-step explanation:

3(x + 3) = 4(4 + 7) => intersecting secant theorem

3(x + 3) = 4(11)

3x + 9 = 44

3x + 9 - 9 = 44 - 9

3x = 35

x = 11.7

You might be interested in
PLEASE HELP!!!!!
Katena32 [7]

Answer:6018

Step-by-step explanation:

Given Sequence

-282-266-250-234.....

It represent an A.P. with

first term a=-282

common difference d=16

So sum of 51 term

S_n=\frac{n}{2}[2a+(n-1)d]

S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]

S_{51}=\frac{51}{2}\times [-564+800]

S_{51}=\frac{51}{2}\times [236]

S_{51}=51\times 118

S_{51}=6018

7 0
3 years ago
If I have a 90 in math, and I have a final exam worth 20% of my grade, what’s the lowest I can get?
8_murik_8 [283]

Answer:

a 40, aka a failing grade ( do ur test :) )

Step-by-step explanation:

6 0
3 years ago
Pls help only b,d, and f
Leya [2.2K]
Solving for y right?

2y = 3x + 4 - x
2y = 2x + 4
y = 2x + 4 over 2
y = 2 (x + 2) over 2
y = x + 2


y - 3 = 2x - 6 over 2
y - 3 = 2(x - 3) over 2
y - 3 = x - 3
y = x


x - y - 2 = 2(2x + 1)
-y - 2 = 2(2x + 1) - x
-y = 2(2x + 1) - x + 2
y = -2(2x + 1) + x - 2
8 0
3 years ago
What what is 90% rounded to the thousandths place
Gemiola [76]
Just move the decimal point 2 spaces to the left if you want it in the hundredth place. <span>.900 is the answer.</span>
8 0
3 years ago
Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu.Assume that the
worty [1.4K]

Answer:

<em>95% confidence interval for the true mean cholesterol content of all such eggs.</em>

<em>(173.8175 , 196.1825)</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the sample  x⁻ = 185 milligrams</em>

<em>Given standard deviation of the sample 'S' = 17.6 milligrams</em>

<em>Level of significance </em>

<em>                  ∝ = 0.05</em>

t_({\frac{\alpha }{2} , n-1 }) = t_{0.025 ,11} =  2.2010

<u><em>Step(ii)</em></u>:-

95% confidence interval for the true mean cholesterol content of all such eggs.

(x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} })

(185 - 2.2010 \frac{17.6}{\sqrt{12} } , 185 + 2.2010 \frac{17.6}{\sqrt{12} })

( 185 - 11.1825 , 185 + 11.1825)

(173.8175 , 196.1825)

<u><em>Final answer:-</em></u>

<em>95% confidence interval for the true mean cholesterol content of all such eggs.</em>

<em>(173.8175 , 196.1825)</em>

<u><em></em></u>

3 0
3 years ago
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