There are 9 female performers in a dance recital. The ratio of men to women is 2:3. How many men are in the dance recital?

Help me with mathhh?!!!!???

DedPeter [7]

Answer:

x = 1 1/4

Step-by-step explanation:

sqrt( 7x+2) = sqrt(3x+7)

Square each side

(sqrt( 7x+2))^2 = (sqrt(3x+7))^2

7x+2 = 3x+7

Subtract 3x from each side

7x-3x +2 = 3x+7-3x

4x+2 = 7

Subtract 2 from each side

4x+2-2 = 7-2

4x = 5

Divide by 4

4x/4 = 5/4

x = 1 1/4

Check for extraneous solution

sqrt( 7*5/4+2) = sqrt(3*5/4+7)

sqrt( 35/4 + 8/4) = sqrt(15/4+28/4)

sqrt( 43/4) = sqrt(43/4)

Solution is valid

3 0

3 years ago

Help please I will give brainleist

Natali5045456 [20]

Answer:

The answer is 80%

8 0

2 years ago

Mr. Alvarado needs 15 1/8 pounds of chicken feed to fill his feeder. He has one bag of chicken feed that weighs 3 1/2 pounds and

Crazy boy [7]

Answer:

B: 8 7/8 Lbs

Step-by-step explanation:

answer = $15\frac{1}{8} -3\frac{1}{2} -2\frac{3}{4}$

step 1 find a common denominator

common denominator - 8

* apply *

$\frac{1^*^1}{8^*^8} =\frac{1}{8} \\\\\frac{1^*^4}{2^*^4} =\frac{4}{8} \\\\\frac{3^*^2}{4^*^2} =\frac{6}{8}$

now we have

$15\frac{1}{8} -3\frac{4}{8} -2\frac{6}{8}$

step 2 make each fraction a improper fraction

We can do this my multiplying the big number by the denominator and adding that to the numerator.

$15*8=120\\120+1=121\\\frac{121}{8} \\\\3*8=24\\24+4=28\\\frac{28}{8} \\\\2*8=16\\16+6=22\\\frac{22}{8}$

now we have

$\frac{121}{8} -\frac{28}{8} -\frac{22}{8}$

Now we can subtract

remember when subtracting fractions you only subtract the numerators. ( so we keep the denominator as 8 )

so 121 - 28 - 22 = 71

so the answer is $\frac{71}{8}$

finally we want to change the answer back into a mixed fraction

To do this we divided 71 and 8

8 can go into 71 8 times

8 * 8 = 64

71 - 64 = 7

We're left with $8\frac{7}{8}$

5 0

3 years ago

Suppose you work for a company that purchases lumber from a major supplier and delivers this lumber to individual clients. Suppo

SpyIntel [72]

Bcbsnbcnnjc va aiaooshshqjjzja s s. Ajajanamark me brainly answered

4 0

3 years ago

What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0

2 years ago