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3 years ago

What is an hypothesis?

Mathematics

2 answers:

Naya [18.7K]3 years ago

5 0

Answer:

Hypothesis

Step-by-step explanation:

Its a theory that you have about something.

vova2212 [387]3 years ago

3 0

Answer: A hypothesis is like a prediction

Hope it helps

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The population of a town increased by 15% in 2016, and decreased by 5% in 2017. If the population of the town was 60,000 in the

nikdorinn [45]

Answer:

The population of the town at the end of 2017 was 65,550.

Step-by-step explanation:

The population of the town was 60,000 in the beginning of 2016.

In 2016, the total population is increased by 15%.

$60,000\times\frac{15}{100}=9000$

Therefore the population is increased by 9000 and the population of the town at the end of 2016 was

$60,000+9000=69,000$

In 2017, the total population is decreased by 5%.

$69,000\times\frac{5}{100}=3450$

Therefore the population is decreased by 3450 and the population of the town at the end of 2017 was

$69,000-3450=65,500$

Therefore the population of the town at the end of 2017 was 65,550.

3 0

3 years ago

Whats the midpoint between 2 and 8

ELEN [110]

Answer: 5

Step-by-step explanation:

8+2=10

10/2=5

7 0

3 years ago

Read 2 more answers

What is the equation of the line that passes through the point (3,-5)(3,−5) and has a slope of 0?

bearhunter [10]

Answer:

y=x-5

Step-by-step explanation:

y=mx+b

-5=0(3)+b

0(3)-5=b

-5=b

y=x-5

Correct me if im wrong

8 0

3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

using the equation G = 10-1.25t. What is the x-intercept of the equation and what is its interpretation in the context of the pr

Masja [62]

Answer:

the x axis is 10, its interpretation is actually G, so on a graph instead of X and Y you would have G and T

8 0

3 years ago