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3 years ago

What is 8/32 in simplest form

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

1/4

Step-by-step explanation:

8 is the greatest common factor of both 8 and 32.

so you divide 8 with 8 which is 1. 32 and 8 is 4 so it would be 1/4

Lyrx [107]3 years ago

5 0

<span>So the question is what is 8/32 in the simplest form. To find out we need to simplify the fraction. In this case the nominator and the denominator are both multiple of 8 so the nominator is 8=1*8 and 32=4*8 so we can write (1*8)/(4*8) and we see that we can cancel out number 8 and get 1/4 which is the simplest form of the fraction. </span>

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A cylinder is placed within a cube. The diameter of the cylinder is equal to the length of each side of the cube. What is the vo

pochemuha

The volume of a shape is the amount of space in it.

<em>The volume outside the cylinder, but inside the cube is 214.6 cubic inches</em>

The given parameter is:

$l = 10$ ---- length of the cube

So, the volume of the cube is:

$V_1 = l^3$

$V_1 = 10^3$

$V_1 = 1000$

The volume of the cylinder is:

$V_2 = \pi r^2h$

The diameter (d) of the cylinder equals the length of the cube.

This means that:

$d = l$

$d = 10$

Divide by 2 to calculate the radius of the cylinder

$r = \frac{10}{2}$

$r = 5$

Also, the height of the cube is::

$h =l$

$h =10$

So, we have:

$V_2 = \pi r^2h$

$V_2 = \pi \times 5^2 \times 10$

$V_2 = \pi \times 25 \times 10$

$V_2 = \pi \times 250$

$V_2 = 785.4$

So, the volume (V) outside the cylinder is:

$V = V_1 - V_2$

$V = 1000 - 785.4$

$V = 214.6$

Hence, the volume outside the cylinder is 214.6 cubic inches

Read more about volumes at:

brainly.com/question/15861918

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3 years ago

WILL MRAK BRAINLIESTTTT IF GOTTEN RIGHT DONT ANSWER IF U DONT KNOW!

il63 [147K]

Answer:

BC=4

Step-by-step explanation:

didn't i do this already lol

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3 years ago

Identify the following series as arithmetic, geometric, both, or neither. 3a + 3a² + 3a³ + . . . + 3an geometric arithmetic neit

kompoz [17]

Answer:

solution

given=3a+3a^2+3a^3+....+...+...3an

first term(t1)=3a

second term(t2)=3a^2

third term(t3)=3a^3

for arithmetic mean ,d1=d2

d1=t2_t1=3a^2_3a=3a(a_1)

d2=3a^3_3a^2=3a^2(a_1)

here d1 is not equal to d2.

so it's not an arithmetic series.

Again,for geometric mean,r1=r2

r1=d2/d1=3a^2/3a=a

r2=d3/d2=3a^3/3a^2=a

here ,r1 is equal to r2.

so ,it's an geometric series.

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Mark is draining his pool to clean it. At 12:00 P.M., he started to drain the pool. At 4:00 P.M., the pool had 11,600 gallons of

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4:00 P.M. to 7:00 P.M. is a total of 3 hours.

This means that from 4:00 p.m to 7:00 P.M. this represents 3/7 of what was lost from 12:00 P.M. to 7:00 P.M.

After knowing this, after doing 11,600 - 6,800 = 4,800
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We then divide 4,800 by 3 which gets 1,600.

Because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200. After adding 11,200 to how much water was left at 7:00 P.M. which was 6,800. 11,200 + 6,800 = 18,000

This means that the pool originally had 18,000 gallons in the pool.

You can also check your work by doing 18,000 - 4(1600), which becomes 1800 - 6400 which gets you 11,600.

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