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trapecia [35]
3 years ago
6

There's a rising issue with bots sending links starting with 'bit'. These links are dangerous and harmful for any computer or de

vice. I'm on the hunt for these bots so that Brainly can take them down for exposing children to a harmful virus. Really appreciate if anyone found some accounts and reported them for posting harmful information on an unknown website.
-Φ
Computers and Technology
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

⚠ warning, there are multiple bots that spam links, that are usually written in a link shortening form (eg, c u t . l y , b i t . l y) do NOT click on those links, as they usually contain trojan viruses, and/or adult content. please copy + paste this message so other users can be aware and stop these bots. thank you, and be safe! :)

Explanation:

hope this helps!

~evita

-Dominant- [34]3 years ago
5 0
Hi there I just posted a question and this pop up

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Write a C program to input a character, then check if the input
rodikova [14]

Answer:

// CPP program to find type of input character

#include <iostream>

using namespace std;

void charCheck(char input_char)

{

// CHECKING FOR ALPHABET

if ((input_char >= 65 && input_char <= 90)

|| (input_char >= 97 && input_char <= 122))

cout << " Alphabet ";

// CHECKING FOR DIGITS

else if (input_char >= 48 && input_char <= 57)

cout << " Digit ";

// OTHERWISE SPECIAL CHARACTER

else

cout << " Special Character ";

}

// Driver Code

int main()

{

char input_char = '$';

charCheck(input_char);

return 0;

}

Explanation:

// CPP program to find type of input character

#include <iostream>

using namespace std;

void charCheck(char input_char)

{

// CHECKING FOR ALPHABET

if ((input_char >= 65 && input_char <= 90)

|| (input_char >= 97 && input_char <= 122))

cout << " Alphabet ";

// CHECKING FOR DIGITS

else if (input_char >= 48 && input_char <= 57)

cout << " Digit ";

// OTHERWISE SPECIAL CHARACTER

else

cout << " Special Character ";

}

// Driver Code

int main()

{

char input_char = '$';

charCheck(input_char);

return 0;

}

6 0
3 years ago
Construct sequence using a specified number of integers within a range. The sequence must be strictly increasing at first and th
natulia [17]

Answer:

Explanation:

The following code is written in Java. It first creates a function that takes in the three parameters to create the sequence, if the sequence is valid it returns the created sequence, otherwise it prints -1 and returns an empty array. The second function called compareSequences takes in to sequences as parameters and compares them, printing out the winner. A test case has been provided in the main method and the output can be seen in the image below.

import java.util.Arrays;

class Brainly {

   public static void main(String[] args) {

       int[] seq1 = createSequence(5, 4, 2);

       int[] seq2 = createSequence(5, 3, 3);

       System.out.println("Winner: " + Arrays.toString(compareSequences(seq1, seq2)));

   }

   public static int[] createSequence(int num, int upperEnd, int lowerEnd) {

       int[] myArray = new int[num];

       int middle = (int) Math.floor(num/2.0);

       myArray[0] = upperEnd;

       myArray[num-1] = lowerEnd;

       int currentValue = upperEnd;

       for (int i = 1; i < num-1; i++) {

           if (i <= middle) {

               myArray[i] = currentValue + 1;

               currentValue += 1;

           } else {

               myArray[i] = currentValue - 1;

               currentValue += 1;

           }

       }

       System.out.println(Arrays.toString(myArray));

       if (myArray[num-2] < lowerEnd) {

           System.out.println("-1");

           int[] empty = {};

           return empty;

       } else {

           return myArray;

       }

   }

   public static int[] compareSequences(int[] seq1, int[] seq2) {

       int lowestLength;

       if (seq1.length > seq2.length) {

           lowestLength = seq2.length;

       } else {

           lowestLength = seq1.length;

       }

       for (int i = 0; i < lowestLength; i++) {

           if (seq1[i] > seq2[i]) {

               return seq1;

           } else if (seq1[i] < seq2[i]) {

               return seq2;

           }

       }

       if (seq1.length > seq2.length) {

           return seq1;

       } else {

           return seq2;

       }

   }

}

7 0
2 years ago
SQL statement to verify the updated name field for the publisher with ID 5 SELECT * FROM Publisher WHERE PubID=5;
hichkok12 [17]

Answer:

Option(a) i.e "true" is the correct answer for the given question.

Explanation:

The select statement is used for fetching the record in the database. Select is the Data manipulation command. The given query gives  all the records where id=5 from the table publisher in the table format.After executing of query the user can verify that the field is updated or not in the table.

So the given statement is "true".

7 0
3 years ago
Which option is most likely used to create many-to-many relationships in Access?
Nastasia [14]

Answer:

Junction table.

Explanation:

Junction table is most likely used to create many-to-many relationships in Access.

A many-to-many relationship comes into existence when one (1) or more items in a table has a relationship with one (1) or more items in another table. An example is the products in a customer order.

Many-to-many relationships provides users with critical and crucial information, they're the most commonly used table relationships in Access.

In order to represent a many-to-many relationship in Access, a third table should be created by the user, this is often referred to as the junction or linking table, which further disintegrate the many-to-many relationship into a two (2) one-to-many relationships.

7 0
3 years ago
In which format is information stored on a hard drive?
Natalija [7]
The answer is binary
6 0
3 years ago
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