Answer:
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Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :

B )
Acceleration a is given by :

Hence , this is the required solution .
The area of a rectangle is calculated by multiplying the length of the rectangle and the width of the rectangle. In this case, the length (the longer side) is 2 2/3 feet while the width (shorter side) is 1 2/3 feet. To multiply fraction, first convert mixed numbers into improper fractions:
2 2/3 = 8/3
1 2/3 = 5/3
Multiplying the two fractions yield:
8/3 x 5/3 = 40/9 ft2
The final answer is 40/9 ft2 or 4 4/9 ft2.
Sure what is it there is no pictuer
The answer to 2x5 is 10 lol