Question

Can someone please help me with this question??

Answer 1

Answer:

The probability that a randomly chosen child in 11th grade and play tennis is 9.6% ⇒ D

Step-by-step explanation:

• P(A) and P(B) =  P(A) . P(B)

• P(A) or P(B) = P(A) + P(B)

The table represents the percentage of the students in each sport

→ The rows represent the grades level, the columns represent the sports

∵ The percentage of students in grade 11 = 40%

∴ The probability of choosing a child in grade 11th = $\frac{40}{100}$ = 0.40

∵ The percentage of students who playing tennis = 24%

∴ The probability of choosing a child who playing tennis = $\frac{24}{100}$ = 0.24

→ We need to find the probability of a randomly chosen child in

   11th grade and playing tennis

∵ The probability of A and B is P(A) . P(B), where P(A) is the probability of

   choosing a child in 11th grade and P(B) is the probability of choosing

   a child playing tennis

∵ P(A) = 0.40 and P(B) = 0.24

∴ P(A) and P(B) = 0.40 × 0.24

∴ P(A) and P(B) = 0.096

→ Change it to a percentage by multiplying it by 100

∴ P(A) and P(B) = 0.096 × 100%

∴ P(A) and P(B) = 9.6%

∴ The probability that a randomly chosen child in 11th grade and

   play tennis is 9.6%