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2 years ago

The varlables x and y vary Inversely. Use the given values to wrke an equation relating X and y

Mathematics

1 answer:

ZanzabumX [31]2 years ago

4 0

X and y vary inversely means y is inversely proportional to x, this means:

y=k/x, where k is a constant.

We are given that when x=-4, y=7/2, we replace these values to find k.

7/2=k/-4
k= (-4*7)/2=-14

So we have y=-14/x

Therefore, when x=4, y=-14/4= -7/2

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Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$

$f(0) = -2$

(0, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 1

$f(1) = 1^{3}-2\cdot (1)^{2}-2$

$f(1) = -3$

(1, -3) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 2

$f(2) = 2^{3}-2\cdot (2)^{2}-2$

$f(2) = -2$

(2, -2) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

x = 3

$f(3) = 3^{3}-2\cdot (3)^{2}-2$

$f(3) = 7$

(3, 7) es un par ordenado de $f(x) = x^{3}-2\cdot x^{2}-2$ .

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

6 0

2 years ago

A radio disc jockey has 7 songs on this upcoming hour's playlist: 2 are rock songs, 2 are reggae songs, and 3 are country songs.

Eddi Din [679]

Probability first song is country is 3/7
probability second song is reggae is 2/6 which reduces to 1/3
probability of both is : 3/7 * 1/3 = 3/21 which reduces to 1/7 <==

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3 years ago

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Mademuasel [1]

Answer:

Step-by-step explanation:

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2 years ago

100 POINTS!!!

dmitriy555 [2]

Answer:

Step-by-step explanation:

The slope of the line parallel to the original line is the same. And you don't add x after the slope.

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1 year ago

I’m not sure how to write this equation. Please check the picture to see the graph for yourself! Help will be much appreciated!

Makovka662 [10]

let's notice something, the parabola is a vertical one, so the squared variable is the x, and is opening downwards, meaning the x² will have a negative coefficient.

the distance from the vertex to the directrix/focus is the amount of "p" units, let's see in the graph, the distance from the vertex to the directrix is 2, and since the parabola is opening downwards, "p" is a negative 2, p = -2. The vertex is of course at (0, 2).

$\bf \textit{parabola vertex form with focus point distance}
\\\\
4p(y- k)=(x- h)^2
\qquad
\begin{array}{llll}
vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\begin{cases}
h=0\\
k=2\\
p=-2
\end{cases}\implies 4(-2)(y-2)=(x-0)^2\implies -8(y-2)=x^2
\\\\\\
y-2=\cfrac{x^2}{-8}\implies \blacktriangleright y=-\cfrac{1}{8}x^2+2 \blacktriangleleft$

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2 years ago