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3 years ago

The varlables x and y vary Inversely. Use the given values to wrke an equation relating X and y

Mathematics

1 answer:

ZanzabumX [31]3 years ago

4 0

X and y vary inversely means y is inversely proportional to x, this means:

y=k/x, where k is a constant.

We are given that when x=-4, y=7/2, we replace these values to find k.

7/2=k/-4
k= (-4*7)/2=-14

So we have y=-14/x

Therefore, when x=4, y=-14/4= -7/2

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Gus purchases 18 apples and 45 pears for his friends. He wants to put the same amount of fruit in each bag. How many bags of fru

Anestetic [448]

Add apples to pears, getting 63, then find the square root which should be 7.937

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3 years ago

Find the value of x in the equilateral triangle. Х 3 in

swat32

Answer:

x≈3.35, or the square root of 11.

Step-by-step explanation:

Use the pythagorian therom. 3²+1.5²=x²

(Half of 3 is 1.5 and the line splits it in half)

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2 years ago

Solve the inequality 13 > 3x + 1

Ivenika [448]

4 > x

step by step explanation:

13 > 3x + 1
-1 -1
12 > 3x
/3 /3
4 > x

3 0

3 years ago

Read 2 more answers

Solve for s. 5/9s+13/9s=24

aleksley [76]

Start by combining like terms:
$( \frac{5}{9} s + \frac{13}{9}s)=24
$
$\frac{5}{9} s + \frac{13}{9}s=2s$

Now we have:
$2s=24$

Divide both sides by 2 to isolate s

$\frac{2s}{2} = \frac{24}{2}$

Final answer:

s=12

3 0

3 years ago

Find n please help me i’m desperate

Rus_ich [418]

Answer:

Step-by-step explanation:

First thing we need to do is to reconcile that r to the negative power. You do that by following the rules for exponents. If

$\frac{x^m}{x^n}$ then the rule is to subtract the lower exponent from the upper:

$x^{m-n}$

Doing that with our base of r:

$\frac{r^3}{r^{-4}}$ is $r^{3-(-4)}$ which is $r^7$

So it looks like what we have now is:

$p^3q^2(p^4q^nr^7)=p^7q^5r^7$

NOW we will follow the rules for multiplying like bases with exponents. The rule for that is if you have like bases and you are multiplying those like bases, you add the exponents. So I'm going to kind of break up that problem and put the like bases together:

$p^3p^4q^2q^nr^7=p^7q^5r^7$

Working on the left side, p to the 3rd times p to the 4 gives you p to the 7th, which is what we have on the right. The r to the 7 is also the same on the left and the right. Working on the q's now, if we have q to the 2nd and we are looking for n, then

$q^{2+n}=q^5$ so 2 + n = 5 and n = 3

7 0

3 years ago

Read 2 more answers