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3 years ago

You are playing Go Fish. How many different 7 card hands can you be dealt from a deck of 52?

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

Answer:

7 with 3 cards left over. I think......

Step-by-step explanation:

goblinko [34]3 years ago

7 0

Answer:

7 total seven card hands can be delt

Step-by-step explanation:

52 divided by 7 equals 7.4 which means only 7 different 7 card hands can be delt

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Pls PLS solve T_T i tried everything

Rudik [331]

Answer:

12√3 is the correct answer

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3 years ago

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Let f(x)=5/x and g(x) =2x^2+5x. What two numbers are not in the domain of F o G?

expeople1 [14]

F(x)=5/x
g(x)=2(x^2)+5x
f(x) has a domain of all real numbers excluding zero
g(x) has a domain of all real numbers
fog(x)=5/(2(x^2)+5x)
fog(x)=5/(x(2x+5))
fog(x) has a domain that excludes both zero and -5/2

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3 years ago

Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per

Dima020 [189]

Answer:

$S \leq 200$

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

$SMS = 16.95 + 0.05S$

For Awesome Wireless, we have:

$SMS = 22.95 + 0.02S$

For Awesome Wireless is greater or equal to Phone R-Us, we have:

$22.95 + 0.02S \geq 16.95 + 0.05S$

Collect Like Terms

$0.02S - 0.05S \geq 16.95 - 22.95$

$-0.03S \geq -6$

Solve for S

$\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}$

$S \leq 200$

Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200

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3 years ago

Show work and explain with formulas.

Juli2301 [7.4K]

20 Answer: a₁ = 4

Step-by-step explanation:

$a_n=324,\ r=3,\ n=5\\\\a_n=a_1 \cdot r^{n-1}\\\\324=a_1\cdot 3^{5-1}\\\\\dfrac{324}{3^4}=a_1\\\\\dfrac{324}{81}=a_1\\\\\large\boxed{4}=a_1$

21 Answer: n = 13

Step-by-step explanation:

$a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n$

22 Answer: n = 5

Step-by-step explanation:

$a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n$

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3 years ago

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Consider the following data:

-BARSIC- [3]

Answer: x =6

Step-by-step explanation:

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3 years ago