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sineoko [7]
3 years ago
9

The dimensions of a solid block of cheese in the shape of a triangular prism are shownbelow.6.9 cm9.9 cm5.1 cm. Which of the fol

lowing is the best estimate of the volume of the block of cheese in cubic centimeters
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

175 cm

Step-by-step explanation:

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Steve and Chris are working together to weed a garden plot. Steve weeded of the plot. Chris weeded of the plot.
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I'm pretty sure its A.
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3 years ago
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What is the sum of the rational expressions below? X/4 + 3/5x
Andrew [12]

Answer:

The answer is  \frac{5x^2+12}{20x} .

Step-by-step explanation:

Given:

X/4 + 3/5x.

Now, to find the sum of the rational expressions.

\frac{x}{4} +\frac{3}{5x}

So, to solve it by adding:

\frac{x}{4} +\frac{3}{5x}

=\frac{5x\times x+3\times 4}{5x(4)}

=\frac{5x^2+12}{20x}

Therefore, the answer is  \frac{5x^2+12}{20x} .

4 0
3 years ago
5. Translate into an equation. Negative seven less than the product of a
elena-s [515]

Answer:

-7-<em>x+-2=-7</em>

Step-by-step explanation:

Negative Seven Less than a product= -7-x

adding negative two= -7-x+-2

this equation equals -7

the equation put together is= -7-<em>x+-2=-7</em>

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<em>Hope this helps</em>

4 0
3 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
Simplify to a single power of 4:<br> 4^7/4^6
Temka [501]

Step-by-step explanation:

\frac{ {4}^{7} }{ {4}^{6} }

= 4

.......

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