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Trava [24]
3 years ago
12

A pitcher of punch is 1/3 full. 7 people share the punch equally. How much of the remaining punch do they each get? *

Mathematics
2 answers:
andrew-mc [135]3 years ago
4 0
Answer: 1/21 1/3 of 21 is 7
Kobotan [32]3 years ago
3 0
They get 1/21 of the pitcher
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PLEASE HELP I NEED HELP!! 25 POINTS
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Kazeer [188]

Answer:

9.364 is the expected number of points.

we can approximate this to 10 points if we want a whole number

Step-by-step explanation:

We have these variables:

[0,5,10,15]

P(x= 0) = p(y>20)+p(y<-20) = 2p(y>20)

P(x=5) = p(-20<=y<=10)+p(10<=y<=20) = 2p(10<=y<=20)

P(x=10) = p(-10<=y<=-3)+p(3<=y<=10) = 2p(3<=y<=10)

P(x=15) = p(-3<=y<=3) = 2p(0<=y<=3)

Z = y/10

Therefore

P(x= 0) = 2(y>20)

= 2p(z>2) = 2(1-p<=2)

= 2(1-0.9772)

= 0.0456

P(x= 5)

= 2p(10<=y<=20)

= 2p(1<=z<=2)

= 2(0.9772-0.8413)

= 0.2718

P(x= 10)

= 2p(3<=y<=10)

= 2p(0.3<=z<=1)

= 2(0.8413-0.6179)

= 0.4468

P(x = 15)

= P(0.6179-0.3821)

= 0.2358

To get expected value of Y

0(0.0456)+5(0.2718)+10(0.4468)+15(0.2358)

= 1.359 + 4.468 + 3.537

= 9.364

E[Y] = 9.364

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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