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DENIUS [597]
3 years ago
8

A player throws a javelin at an unknown angle with a horizontal velocity 20 m/s and vertical velocity 60 m/s. Find its angle and

resultant velocity.
Physics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

63º~64º

Explanation:

so imagine a graphic with a triangle. The distance between the zero and the horizontal (x) is 20 and the distance between 0 and vertical (y) is 60

20 = base

60 = height

hypotenuse = L

tg = cato/cata

tg = 60/20

tg = 2

I give up

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An object is taken from an oven at 350o F and left to cool in a room at 70o F. If the temperature fell to 250o F in one hour, wh
Oksana_A [137]

Answer:

117.83° F

Explanation:

Using Newton's Law of Cooling which can be expressed as:

\dfrac{dT}{dt}= k(T-T_1)

The differential equation can be computed as:

\dfrac{dT}{dt}= k(T-70)

\dfrac{dT}{(T-70)}= kdt

\int \dfrac{dT}{(T-70)}= \int kdt

In|T-70| = kt +C

T- 70 = e^{kt+C} \\ \\ T = 70+e^{kt+C} \\ \\ T = 70 + C_1e^{kt}  --- (1)

where;

C_1 = e^C

At the initial condition, T(0)= 350

350 = 70 C_1^{k*0}

350 -70 = C_1

280 = C_1

replacing C_1= 280 into (1)

Hence, the differential equation becomes:

T(t) = 70 + 280 e^{kt}

when;

time (t) = 1 hour

T(1) = 250

Since;

250 = 70 + 280 e^{k*1}

180 = 280e^k \\ \\ \dfrac{180}{280}= e^k

k = In (\dfrac{180}{280})

k = -0.4418

Therefore;

T(t) = 70 + 280e^{(-0.4418)}t

After 4 hours, the temperature is:

T(t) = 70 + 280e^{(-0.4418)}4

T(4) = 117.83° F

7 0
3 years ago
"An alpha particle (He2+) with a velocity of 2.6x106m/scrosses a uniform magnetic field at an angle of 37.0°to the field lines a
sergey [27]

Answer:

B = 5.59x10⁹ T

Explanation:

The magnetic force (F), on a the alpha particle with charge (q) that is moving at velocity (v) as the cross product of the velocity and magnetic field (B) is:

F = qvBsin(\theta)

<u>We have:</u>

F = 1.4x10⁻³ N

v = 2.6x10⁶ m/s

θ = 37.0°

q = 2*p = 2*1.6x10⁻¹⁹ C

Hence, the strength of the magnetic field is:

B = \frac{F}{qvsin(\theta)} = \frac{1.4 \cdot 10^{-3}}{1.6 \cdot 10^{-19} C*2.6 \cdot 10^{6}*sin(37)} = 5.59 \cdot 10^{9} T

Therefore, the strength of the magnetic field is 5.59x10⁹ T.

I hope it helps you!

7 0
3 years ago
True or false: seismographs from three locations are studied to calculate the epicenter of am earthquake
astraxan [27]
True........don't blame me if i'm wrong.<span />
7 0
3 years ago
(20 POINTS!)
vovikov84 [41]
121 is the answer to your question
3 0
4 years ago
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____ is a chemical messenger released by virus infected cells
MaRussiya [10]

Answer:

Cytokines is the answer

Explanation:

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