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sasho [114]
3 years ago
12

Two identical soccer balls are rolled towards each other. What will be true after they collide head-on

Physics
2 answers:
tresset_1 [31]3 years ago
8 0
They will go away from each other
Furkat [3]3 years ago
6 0

Answer:

(v_{i_{1} }+v_{i_{2} }) = (v_{f_{1} }+v_{f_{2} })

Explanation:

There are some things we can say:

  • If the Collision was Elastic, then the conservation of energy applies, where the kinetic energy of the system before they collide will be the same after they collide.
  • If the collision was inelastic, then we can assert that the kinetic energy of the system before the collision and after the collision will be different, because there is some energy lost in the form of heat for example, though the energy of the entire system stays the same (if we add the losses).
  • The law of conservation of momentum states that the momentum of the system before the collision is exactly the same after the collision so if m_{1} =m_{2}:

m_{i_{1} } *v_{i_{1} }+m_{i_{2} } *v_{i_{2} } = m_{f_{1} } *v_{f_{1} }+m_{f_{2} } *v_{f_{2} }

m_{i_{1} } *(v_{i_{1} }+v_{i_{2} }) = m_{f_{1} } *(v_{f_{1} }+v_{f_{2} })

Since there is conservation of mass as well (we assume that nothing breaks apart after the collision):

(v_{i_{1} }+v_{i_{2} }) = (v_{f_{1} }+v_{f_{2} })

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Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

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Answer:

I hope this helps and I'm not to late

A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.

Explanation:

you also can use paraphrase to help you reword bye bye!!

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