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sasho [114]
3 years ago
12

Two identical soccer balls are rolled towards each other. What will be true after they collide head-on

Physics
2 answers:
tresset_1 [31]3 years ago
8 0
They will go away from each other
Furkat [3]3 years ago
6 0

Answer:

(v_{i_{1} }+v_{i_{2} }) = (v_{f_{1} }+v_{f_{2} })

Explanation:

There are some things we can say:

  • If the Collision was Elastic, then the conservation of energy applies, where the kinetic energy of the system before they collide will be the same after they collide.
  • If the collision was inelastic, then we can assert that the kinetic energy of the system before the collision and after the collision will be different, because there is some energy lost in the form of heat for example, though the energy of the entire system stays the same (if we add the losses).
  • The law of conservation of momentum states that the momentum of the system before the collision is exactly the same after the collision so if m_{1} =m_{2}:

m_{i_{1} } *v_{i_{1} }+m_{i_{2} } *v_{i_{2} } = m_{f_{1} } *v_{f_{1} }+m_{f_{2} } *v_{f_{2} }

m_{i_{1} } *(v_{i_{1} }+v_{i_{2} }) = m_{f_{1} } *(v_{f_{1} }+v_{f_{2} })

Since there is conservation of mass as well (we assume that nothing breaks apart after the collision):

(v_{i_{1} }+v_{i_{2} }) = (v_{f_{1} }+v_{f_{2} })

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When you walk at an average speed (constant speed, no acceleration) of 20.7 m/s in 75.8 sec you will cover a distance of______?
nlexa [21]
1,569.06m
(20.7•75.8)
3 0
3 years ago
A ball is dropped from 8.5 meters above the ground. If it begins at rest, how long does it take to hit the ground?
Anna35 [415]

Answer:

Explanation:

Givens

d = 8.5 meters

vi = 0

a = 9.81

t = ?

Formula

d = vi * t + 1/2 a t^2

Solution

8.5 = 0 + 1/2 9.81 * t^2       multiply both sides by 2

8.5 = 4.095 t^2                  Divide both sides by 4.095

8.5/4.095 = t^2

1.7329 = t^2                       Take the square root of both sides

t = 1.316

It takes 1.316 seconds to hit the ground.

6 0
3 years ago
A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the distance the car travels during this time.
andrew11 [14]
It traveled 39.6 meters
6 0
3 years ago
Read 2 more answers
I just need an answer ASAP
nikdorinn [45]

Answer: c

Explanation: hope this helps :)

8 0
2 years ago
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A body moving with an initial velocity of 30m/s accelerates uniformly at the rate of 10m/s . what is the distance covered during
nikdorinn [45]

Answer:

The distance covered by the body is, S = 800 m

Explanation:

Given data,

The initial velocity of the body, u = 30 m/s

The acceleration of the body, a = 10 m/s²

Let the time period of travel be, t = 10 s

Using the II equations of motion,

                       S = ut + ½ at²

Substituting the given values,

                        S = 30 x 10 + ½ x 10 x 10²

                         S = 800 m

Hence, the distance covered by the body is, S = 800 m

5 0
3 years ago
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