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andrey2020 [161]
3 years ago
13

A marathon runner runs at a steady 15 km/hr. When the runner is 7.5 km from the finish, a bird begins flying from the runner to

the finish at 30 km/hr. When the bird reaches the finish line, it turns around and flies back to the runner, and then turns around again, repeating the back-andforth trips until the runner reaches the finish line. How many kilometers does the bird travel?
Physics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

The value is D =  15 \  km

Explanation:

From the question we are told that

   The  speed of the marathon runner is  v  =  15 \  km /hr

   The distance from the distance from the finish is  d =  7.5 \  km

   The  speed of the bird is  v_b  =  30 \ km / hr

  Generally the time taken for the runner to reach the finish is mathematically represented as

       t =  \frac{d}{v}

       t =  \frac{7.5}{15}

        t =  \frac{1}{2}

So the distance covered by the bird is  

      D =  v_b  *  t

      D =  30  *  \frac{1}{2}

         D =  15 \  km

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ONLINE CALCULATOR .A force of 187 pounds makes an angle of 73 degrees 36 ' with a second force. The resultant of the two forces
saul85 [17]

Answer:

The magnitudes of the second force is   Z = 129.9 N

The magnitudes of the  resultant force is   R = 256.047 N

Explanation:

From the question we are told that  

    The force is  F = 187 \ lb

     The angle made with second force \theta_o = 73 ^o 36' =  73 + \frac{36}{60}  =  73.6^o

     The angle between the resultant force and the first force \theta _1  = 29 ^o 1 ' = 29 + \frac{1}{60}  = 29.0167^o

For us to solve problem we are going to assume that

     The magnitude of the second force is  Z N

     The magnitude of the resultant force is R N

According to Sine rule

                \frac{F}{sin (\theta _o - \theta_1 }  = \frac{Z}{\theta _1}

Substituting values

             \frac{187}{sin(73.3 - 29.01667)} =\frac{Z}{sin (29.01667)}  

             267.82 =\frac{Z}{0.4851}  

              Z = 129.9 N

According to cosine rule

       R = \sqrt{F ^2 + Z^2 + 2(F) (Z) cos (\theta _o) }

Substituting values

     R = \sqrt{187^2 + 129.9 ^2  + 2 (187 ) (129.9) cos (73.6)}

     R = 256.047 N

 

3 0
3 years ago
Your oven has a power rating of 5000 watts. How many kilowatts is this ?
Gekata [30.6K]

1,000 watts = 1 kilowatt
2,000 watts = 2 kilowatts
3,000 watts = 3 kilowatts
4,000 watts = 4 kilowatts
<em>5,000 watts = 5 kilowatts</em>

8 0
3 years ago
What instrument uses a magnetic field to magnify imags up to 100000000?
Mariana [72]
Transmission electron microscope
5 0
3 years ago
Physics is really confusing...is there anyone that can show it to me?
coldgirl [10]

Answer:

1.0×10³ N

Explanation:

μs is the static coefficient of friction.  That's the friction that acts on a stationary (non-moving) object when being pushed or pulled.

μk is the kinetic coefficient of friction.  That's the friction that acts on a moving object.

To budge the pig (while it's still stationary), we need to overcome the static friction.

F = N μs

For a non-moving object on level ground, the normal force N equals the weight.

F = mg μs

Given m = 130 kg and μs = 0.80:

F = (130 kg) (9.8 m/s²) (0.80)

F = 1019.2 N

Rounded to two significant figures, the force needed to budge the pig is 1.0×10³ N.

3 0
3 years ago
A 2.0-kg cart collides with a 1.0-kg cart that is initially at rest on a low-friction track. After the collision, the 1.0-kg car
nikitadnepr [17]

To solve this problem we will apply the concepts related to the conservation of momentum. The momentum can be defined as the product between the mass of the object and its velocity, and the conservation of the momentum as the equality between the change of the initial momentum versus the final momentum. Mathematically, this relationship can be described as

m_1u_1+m_2u_2 = m_1v_2+m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2} = Final velocity of each object

According to the statement one of the bodies does not have initial velocity, therefore said term would be zero. And the equation could be rewritten as,

m_1u_1= m_1v_2+m_2v_2

Replacing the values respectively (The mass of your body with its respective speed we would have)

2kg(u_1) = 2kg(0.3m/s)+1kg(0.5m/s)

u_1 = \frac{2kg(0.3m/s)+1kg(0.5m/s)}{2kg}

u_1 = 0.55m/s

Therefore the initial velocity of the 2kg cart is 0.55m/s

4 0
3 years ago
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