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Mandarinka [93]
3 years ago
6

Yeahhh, please help :,) :DDDD

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0

Answer:

-46

Step-by-step explanation:

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Emma had 10 Balls in a bag. The balls were numbers 1 through 10. She wanted to test the probability of drawing a ball that is a
Goryan [66]

Answer:

  • 30%
  • Unlikely

Step-by-step explanation:

<u>The balls - multiples of 3 are:</u>

  • 3, 6 and 9

<u>The probability of a multiple of 3 is:</u>

  • 3 out of 10 or
  • P = 3/10 = 30%

30% probability is in the range 0%-50% so this event is unlikely

5 0
3 years ago
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Simplify the expression below.<br> 4+2^3 -|-4|
pantera1 [17]
Answer:

8

Explanation:

Too lazy to type it all
5 0
3 years ago
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A cube has six sides that are numbered 1 to 6. The sides numbered 1, 2, and 5 are green, and the sides numbered 3, 4,
Katarina [22]

Answer:

5/6

Step-by-step explanation:

The sides numbered 1,2,5 are green and 2,4,6 are even  

We cannot count the 2 twice, so there are 5 unique possibilities of getting either a green or an even

There are 6 total possibilities when rolling the die  1,2,3,4,5,6

P (green or even) = green or even/ total

                             = 5/6

8 0
3 years ago
Please help me, please and thank youuu! :D
katen-ka-za [31]

Answer:

f = - \frac{19}{7}

Step-by-step explanation:

Given f varies directly with m then the equation relating them is

f = km ← k is the constant of variation

To find k use the condition f = - 19 when m = 14

- 19 = 14k ( divide both sides by 14 )

- \frac{19}{14} = k

f = - \frac{19}{14} m ← equation of variation

When m = 2 , then

f = - \frac{19}{14} × 2 = - \frac{19}{7}

8 0
2 years ago
two bags contains 10 balls each. Every round you choose with equal probability one of the two bags and pick out a ball. After a
Stells [14]

Answer:

6.10%

Step-by-step explanation:

For every round since we are choosing with equal probability, then the probability of choosing from either of the bags is 1/2

Here, this scenario is only possible when a particular bag has been chosen 10 times and the other bag has been chosen 6 times ( meaning a particular bag has been emptied and for a particular bag to be emptied, all of its content would have been picked)

Now on the 17th trial, an empty bag is chosen

Therefore the required probability will be;

16C0 * (1/2)^10 * (1/2)^6 * 1/2 = 0.0610 = 6.1%

4 0
4 years ago
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