Step-by-step explanation:
Since both lines intersect each other 3 units above the x-axis, the y-value of the point of intersection must be 3.
Looking at the options, (-3, 5), (3, -2) and (0, -3) are all invalid points.
I'm assuming the the numbers coming after the variables are meant to be exponents, and if I'm wrong just let me know
-3x^4 - 2x^3 + 3x^2 + 3x^4 - 4x^3 + x^2, rearrange to have like terms in order
-3x^4 +3x^4 - 2x^3 - 4x^3 +3x^2 + x^2, now simplify
0 -6x^3 + 4x^2
The answer is C (SAS)
Explanation:
AC = EC
BC = DC
angle ACB = angle DCE (Vertically Opposite Angles)
Therefore, the triangles are congruent by the Side-Angle-Side congruency
The answer is: " (x² − 3) " .
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Explanation:
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Given: 3x² <span>− 9x ; factor out a "3x" ;
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</span>→ 3x (x² − 3) ;
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The answer is: " (x² − 3) " .
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Answer:
27, you need to simplify both sides of the equation to get x on one side.
Step-by-step explanation:
