Answer:
The possible length is greater than 29 meters.
Step-by-step explanation:
If the length is x then the width is x - 2 m.
So the perimeter is 2x + 2(x - 2) = 4x - 4 m.
4x - 4 > 112
4x > 116
x > 29 m.
Answer:
Perpendicular
Step-by-step explanation:
Intersect over each other
Answer:
The first diagram is the correct one
Step-by-step explanation:
Notice that the subtraction of two complex numbers (z1- z2) implies the use of the opposite for the real and imaginary part of the complex number that is subtracted (in our case of z2). When we do such, the complex number z2 gets reflected about the origin (0,0), and then the real components of the two numbers get added among themselves and the imaginary components get added among themselves.
The diagram that shows such reflection about the origin [ z2 = 3 + 5 i being converted into -3 - 5 i] and then the combination of real parts [-3 + 5 = 2] and imaginary parts [-5 i - 3 i = - 8 i], is the very first diagram shown.
Can you show me a picture of the problem?
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx =
and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx =
and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet