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4 years ago

Please assist me with #14

Mathematics

1 answer:

Eddi Din [679]4 years ago

4 0

Answer:

a, c) see below

b) trapezoid

d) 80 square units

Step-by-step explanation:

a, b, c) See the attached plot. The different-length horizontal bases make this a trapezoid.

d) The area of the original is ...

A = (1/2)(b1 +b2)h = (1/2)(1+4)(2) = 5

Dilation by a factor of 4 multiplies the area by a factor of 4² = 16.

The area of the larger trapezoid is ...

5 × 16 = 80 . . . . square units

Of course, you can use the area formula, too:

A = (1/2)(b1 +b2)h = (1/2)(4 +16)(8) = 80 . . . . square units

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A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with t

zaharov [31]

Answer:

a. 0.2

b. 0.42

c. 0.7

d. the solution is in the explanation

e. x and y are not independent

Step-by-step explanation:

a. from the joint probability mass function table,

p(x=1) and p(Y= 1)

= p(1,1) = 0.2

b. prob(0,0)+prob(0,1)+prob(1,0)+prob(1,1)

= 0.10 + 0.04 + 0.08 + 0.20

= 0.42

P(X ≤ 1 and Y ≤ 1) = 0.42

c. prob {X ≠ 0 and Y ≠ 0}

= prob(1,1) + prob(1,2) + prob(2,1) + prob(2,2)

= 0.20 + 0.06 + 0.14 + 0.30

= 0.7

d. we have to calculate the marginal pmf of x and y here.

we have the x values as 0,1,2

prob(x=0) = 0.1 + 0.04 + 0.02

= 0.16

prob(x=1) = 0.08 + 0.2 + 0.06

= 0.34

prob(x=2) = 0.06+0.14+0.3

= 0.50

we have y values as 0,1,2

prob(y=0) = .1+.08+.06

= 0.24

prob(y=1) = .04+.2+.14

= 0.38

prob(y = 2) = 0.02+0.06+0.3

= 0.38

P(X ≤ 1) = prob(x=0)+prob(x=1)

= 0.34+0.16

= 0.50

e. from the joint table we have this,

prob(1,1) = 0.2

prob(x=1) = 0.34

prob(y=1) = 0.38

then prob(x=1)*prob(y=1)

= 0.34*0.38

= 0.1292

therefore prob(1,1) is not equal to prob(x=1)*prob(y=1)

0.2≠0.1292

x and y are not independent

7 0

3 years ago

For what values of x is x2-36=5x true? 0 -9 and -4 O4 and 9 O4 and -9 o 9 and 4

mars1129 [50]

Answer:

-4 and 9

Step-by-step explanation:

we have

$x^{2} -36=5x$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} -36=5x$

$x^{2}-5x-36=0$

$a=1\\b=-5\\c=-36$

substitute in the formula

$x=\frac{-(-5)(+/-)\sqrt{-5^{2}-4(1)(-36)}} {2(1)}$

$x=\frac{5(+/-)\sqrt{169}} {2}$

$x=\frac{5(+/-)13} {2}$

$x=\frac{5(+)13} {2}=9$

$x=\frac{5(-)13} {2}=-4$

therefore

The equation is true for -4 and 9

4 0

3 years ago

Please somebody help need an answer

777dan777 [17]

B. 3,800 is the answer

5 0

3 years ago

Identify the y-intercept (initial value) in the function f(x)=130.27)x

SpyIntel [72]

Y intersect is 7 because if you make the graph you can match it.

4 0

3 years ago

Which step is the most efficient way to find the solution of x + 4 > -8?-

lesya [120]

Answer:

see explanation

Step-by-step explanation:

given

x + 4 > - 8 ( subtract 4 from both sides )

x > - 12 ← solution

The step to use is subtract 4 from both sides

6 0

3 years ago

Read 2 more answers

Please assist me with #14​

Please assist me with #14