Calculate the vapor pressure (in torr) of a solution containing 0.2 moles of solute dissolved in 10 moles of water at 25°C. Vapo r pressure of pure water at 25°C is 23.8 torr. Enter text here Enter 2021 Acellus Corporation. All Rights Reserved. C
2 answers:
your answer is: 22.9 torr at 25°C
Explanation:
When a non volatile solute is added to a pure solvent, the vapour pressure of the mixture decrease regard to the pure solvent following the equation
Where vapour pressure of the pure solvent (Water) is 23.8torr at 25°C.
Mole fraction of water is the ratio between moles of water and total moles in solution. The solution has a mole fraction of water of:
Replacing in Raoult's law:
Vapor pressure of the solution is 22.9 torr at 25°C
hope this helps!
Answer:
the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (180.2 g/mole) in 250.0 mL of water. The vapor pressure of pure water at 25°C
Step-by-step explanation:
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Answer:
8.3
Step-by-step explanation:
25÷3=8.3333333
I rounded it to this.
Explanation is in the file
tinyurl.com/wpazsebu
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