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frutty [35]
3 years ago
6

Calculate the vapor pressure (in torr) of a solution containing 0.2 moles of solute dissolved in 10 moles of water at 25°C. Vapo

r pressure of pure water at 25°C is 23.8 torr. Enter text here Enter 2021 Acellus Corporation. All Rights Reserved. C​
Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

your answer is:  22.9 torr at 25°C

Explanation:

When a non volatile solute is added to a pure solvent, the vapour pressure of the mixture decrease regard to the pure solvent following the equation

Where vapour pressure of the pure solvent (Water) is 23.8torr at 25°C.

Mole fraction of water is the ratio between moles of water and total moles in solution. The solution has a mole fraction of water of:

Replacing in Raoult's law:

Vapor pressure of the solution is 22.9 torr at 25°C

hope this helps!

Gnesinka [82]3 years ago
3 0

Answer:

the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (180.2 g/mole) in 250.0 mL of water. The vapor pressure of pure water at 25°C

Step-by-step explanation:

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mariarad [96]

Answer:

c is the same angle as a

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3 0
3 years ago
Read 2 more answers
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
Reflected across the x-axis and vertically<br> translated up 2 units.
Korvikt [17]

Incomplete question.

7 0
3 years ago
Given ΔACD and ΔABE, what is AB?
AleksAgata [21]
Well we don’t know what’s given
5 0
3 years ago
The perimeter of a triangle is 49ft. One side of the triangle is 17ft shorter than the second side. The third side is 6ft shorte
Phoenix [80]

Answer:

7,24,18

Step-by-step explanation:

perimeter of a triangle = a₁ + a₂ + a₃

A/Q

let, 2nd side = x

then, 1st side =x-17

3rd side = x-6

perimeter= 49

.:

49 = (x-17)+ x + (x-6)

49 = x-17+x+x-6

49 = 3x -23

3x = 49+23

3x = 72

x = 72/3

x= 24

.:

1st side = (x-17) = 24-17=7

1st side= 7

2nd side = x = 24

3rd side = x-6

=24-6

=18

3rd side = 18

on calculating perimeter = 7+24+18=49.

Hope it helps:)

8 0
3 years ago
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